Mike will jog form home at x miles per hour and then walk back home by the same route at y miles per hour. How many miles from home can Mike jog so that he spends a total of t hours jogging and walking?
a) xt/y
b) x+t/xy
c) xyt/x+y
d) x+y+t /xy
e) y+t/x - t/y
I tried to do it using numbers but could not get the correct answer.
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truplayer256
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Is the OA C?
Since the number of miles that Mike is going to jog for and walk for are the same, let d equal the distance. So,
d/y+d/x=t
solve for d..
xd+dy/yx=t
tyx=xd+dy
tyx=d(x+y)
tyx/x+y=d
Since the number of miles that Mike is going to jog for and walk for are the same, let d equal the distance. So,
d/y+d/x=t
solve for d..
xd+dy/yx=t
tyx=xd+dy
tyx=d(x+y)
tyx/x+y=d
OA is C.truplayer256 wrote:Is the OA C?
Since the number of miles that Mike is going to jog for and walk for are the same, let d equal the distance. So,
d/y+d/x=t
solve for d..
xd+dy/yx=t
tyx=xd+dy
tyx=d(x+y)
tyx/x+y=d
