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by bhumika.k.shah » Sat Jan 23, 2010 11:14 am
OA D

Ok i need some serious help !
there has to be an easy way which is not striking to me this very moment!
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by sreak1089 » Sat Jan 23, 2010 11:36 am
Let me assume the symbol that you have given in the document is % (since that symbol does not appear on the keyboard). a % b indicates -> the remainder when a is divided by b.

((98 % 33) % 17) - (98 % (33 % 17))

Now we need to use BODMAS method to solve this. First compute the inner expression:

98 % 33 = 32 (since remainder when 98 is divided by 33 is equal to 32).

Thus, we have:

(32 % 17) - (98 % (33 % 17))

Now lests compute the inner expression (33 % 17):

(33 % 17) = 16 (remainder when 33 is divided by 17)

Now we have:

(32 % 17) - (98 % 16)

= 15 - 2 = 13

Hope that Helps !
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by bhumika.k.shah » Sat Jan 23, 2010 11:43 am
hey now it looks quite simple :-D
thanks!

i guess i got freaked out looking at soo many #s and the weird symbol tht i dint quite read the question properly...
:-P
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by thephoenix » Sat Jan 23, 2010 6:15 pm
bhumika.k.shah wrote:OA D

Ok i need some serious help !
there has to be an easy way which is not striking to me this very moment!
(98@33)@17=32@17=15
98@(33@17)=98@16=2
15-2=13
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