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Algebra

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by tohellandback » Mon Aug 10, 2009 11:51 pm
4x<x, x must be negative
x<x^3, x must be a fraction

-1<X<0

D is the answer
The powers of two are bloody impolite!!
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by hariharakarthi » Tue Aug 11, 2009 5:02 am
@tohellandback

x<x^3, x must be a fraction How did you come to this?

I think it should X^3<X^2 here, hence X must be a fraction.

Hence, Ans should be fraction and -ve.
Out of 5 Ans choices 2 (-3/2, -1/2) satisfies this condition
Apply these 2 and check the condtion.

Correct Ans D.
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by tohellandback » Tue Aug 11, 2009 7:19 am
hariharakarthi wrote:@tohellandback

x<x^3, x must be a fraction How did you come to this?

I think it should X^3<X^2 here, hence X must be a fraction.

Hence, Ans should be fraction and -ve.
Out of 5 Ans choices 2 (-3/2, -1/2) satisfies this condition
Apply these 2 and check the condtion.

Correct Ans D.
for negative fractions, x<x^3 is correct. I don't think there is any problem with that.
for ex:-1/2<-1/8
The powers of two are bloody impolite!!
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