BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Try this one

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
User avatar
Senior | Next Rank: 100 Posts
Posts: 79
Joined: Thu Oct 23, 2008 9:28 am
Location: Canada
Thanked: 1 times
GMAT Score:700

Try this one

by adilka » Mon Jan 12, 2009 8:36 pm
AB + CD = AAA, where AB and CD are two-digit numbers and AAA is a three digit number; A, B, C, and D are distinct positive integers. In the addition problem above, what is the value of C?

(A) 1

(B) 3

(C) 7

(D) 9

(E) Cannot be determined
Top
Source: — Problem Solving |
Master | Next Rank: 500 Posts
Posts: 259
Joined: Thu Jan 18, 2007 8:30 pm
Thanked: 16 times

by amitabhprasad » Mon Jan 12, 2009 8:47 pm
I am getting "9"
Top
Senior | Next Rank: 100 Posts
Posts: 60
Joined: Wed Jan 07, 2009 1:56 pm
Thanked: 12 times
GMAT Score:750

by arzanr » Mon Jan 12, 2009 8:48 pm
Ans would be E.

AAA has to be 111 because you cannot get 222 or above by adding two 2digit numbers.

Therefore, 13 + 98 = 111 and 17 + 94 = 111. As a result C cannot be determined.
Top
Legendary Member
Posts: 2467
Joined: Thu Aug 28, 2008 6:14 pm
Thanked: 331 times
Followed by:11 members

by cramya » Mon Jan 12, 2009 8:52 pm
17
94

111

So c is 9 (1 will be the carry over so c will always be 9)
Last edited by cramya on Mon Jan 12, 2009 8:54 pm, edited 1 time in total.
Top
Legendary Member
Posts: 2467
Joined: Thu Aug 28, 2008 6:14 pm
Thanked: 331 times
Followed by:11 members

by cramya » Mon Jan 12, 2009 8:53 pm
Azanr,
Would c not always be 9 in both ur cases?
Top
Senior | Next Rank: 100 Posts
Posts: 60
Joined: Wed Jan 07, 2009 1:56 pm
Thanked: 12 times
GMAT Score:750

by arzanr » Mon Jan 12, 2009 8:55 pm
cramya wrote:Azanr,
Would c not always be 9 in both ur cases?
Haha you're right.. I mixed up C and D.. I just got done with doing a full timed practice test so a little weary :)
Top
Legendary Member
Posts: 2467
Joined: Thu Aug 28, 2008 6:14 pm
Thanked: 331 times
Followed by:11 members

by cramya » Mon Jan 12, 2009 9:00 pm
Haha you're right.. I mixed up C and D.. I just got done with doing a full timed practice test so a little weary

It happens; nice solution though!
Top
User avatar
Senior | Next Rank: 100 Posts
Posts: 79
Joined: Thu Oct 23, 2008 9:28 am
Location: Canada
Thanked: 1 times
GMAT Score:700

by adilka » Mon Jan 12, 2009 10:18 pm
Correct folks. OA is 9, D
Last edited by adilka on Tue Jan 13, 2009 1:15 pm, edited 1 time in total.
Top
Senior | Next Rank: 100 Posts
Posts: 73
Joined: Wed Jan 07, 2009 1:00 pm
Location: Tampa, FL
Thanked: 9 times
GMAT Score:630

by Mr2Bits » Tue Jan 13, 2009 8:21 am
adilka wrote:Correct folks. OA is 9, E
Answer is 9 (D) was no other value satisfies AAA having to equal 111.
Top
Master | Next Rank: 500 Posts
Posts: 424
Joined: Sun Dec 07, 2008 5:15 pm
Location: Sydney
Thanked: 12 times

by piyush_nitt » Wed Jan 14, 2009 4:17 am
Mr2Bits wrote:
adilka wrote:Correct folks. OA is 9, E
Answer is 9 (D) was no other value satisfies AAA having to equal 111.

How about

84 + 27

74 + 37

Above eqn , equates to 111

Anything wrong in my logic?
Top
Senior | Next Rank: 100 Posts
Posts: 73
Joined: Wed Jan 07, 2009 1:00 pm
Location: Tampa, FL
Thanked: 9 times
GMAT Score:630

by Mr2Bits » Wed Jan 14, 2009 7:42 am
piyush_nitt wrote:
Mr2Bits wrote:
adilka wrote:Correct folks. OA is 9, E
Answer is 9 (D) was no other value satisfies AAA having to equal 111.

How about

84 + 27

74 + 37

Above eqn , equates to 111

Anything wrong in my logic?
Yes your logic is flawed becuase in your case you would be needing to satisfy 888 (AB=84(A=8)) or 777(AB=74(A=7))

The question is asking for two, two digit postive integers when added together equal a 3 digit positve integer where all three digits are the same(this is your A value). Only option is AAA= 111
Top
Master | Next Rank: 500 Posts
Posts: 424
Joined: Sun Dec 07, 2008 5:15 pm
Location: Sydney
Thanked: 12 times

by piyush_nitt » Wed Jan 14, 2009 7:56 pm
Mr2Bits wrote:
piyush_nitt wrote:
Mr2Bits wrote:
adilka wrote:Correct folks. OA is 9, E
Answer is 9 (D) was no other value satisfies AAA having to equal 111.

How about

84 + 27

74 + 37

Above eqn , equates to 111


Got it ..Thanks !

Missed that part.

Anything wrong in my logic?
Yes your logic is flawed becuase in your case you would be needing to satisfy 888 (AB=84(A=8)) or 777(AB=74(A=7))

The question is asking for two, two digit postive integers when added together equal a 3 digit positve integer where all three digits are the same(this is your A value). Only option is AAA= 111
Top
Post new topic Post Reply
• Page 1 of 1