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by adilka » Mon Jan 12, 2009 8:36 pm
AB + CD = AAA, where AB and CD are two-digit numbers and AAA is a three digit number; A, B, C, and D are distinct positive integers. In the addition problem above, what is the value of C?

(A) 1

(B) 3

(C) 7

(D) 9

(E) Cannot be determined
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by amitabhprasad » Mon Jan 12, 2009 8:47 pm
I am getting "9"
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by arzanr » Mon Jan 12, 2009 8:48 pm
Ans would be E.

AAA has to be 111 because you cannot get 222 or above by adding two 2digit numbers.

Therefore, 13 + 98 = 111 and 17 + 94 = 111. As a result C cannot be determined.
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by cramya » Mon Jan 12, 2009 8:52 pm
17
94

111

So c is 9 (1 will be the carry over so c will always be 9)
Last edited by cramya on Mon Jan 12, 2009 8:54 pm, edited 1 time in total.
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by cramya » Mon Jan 12, 2009 8:53 pm
Azanr,
Would c not always be 9 in both ur cases?
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by arzanr » Mon Jan 12, 2009 8:55 pm
cramya wrote:Azanr,
Would c not always be 9 in both ur cases?
Haha you're right.. I mixed up C and D.. I just got done with doing a full timed practice test so a little weary :)
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by cramya » Mon Jan 12, 2009 9:00 pm
Haha you're right.. I mixed up C and D.. I just got done with doing a full timed practice test so a little weary

It happens; nice solution though!
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by adilka » Mon Jan 12, 2009 10:18 pm
Correct folks. OA is 9, D
Last edited by adilka on Tue Jan 13, 2009 1:15 pm, edited 1 time in total.
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by Mr2Bits » Tue Jan 13, 2009 8:21 am
adilka wrote:Correct folks. OA is 9, E
Answer is 9 (D) was no other value satisfies AAA having to equal 111.
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by piyush_nitt » Wed Jan 14, 2009 4:17 am
Mr2Bits wrote:
adilka wrote:Correct folks. OA is 9, E
Answer is 9 (D) was no other value satisfies AAA having to equal 111.

How about

84 + 27

74 + 37

Above eqn , equates to 111

Anything wrong in my logic?
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by Mr2Bits » Wed Jan 14, 2009 7:42 am
piyush_nitt wrote:
Mr2Bits wrote:
adilka wrote:Correct folks. OA is 9, E
Answer is 9 (D) was no other value satisfies AAA having to equal 111.

How about

84 + 27

74 + 37

Above eqn , equates to 111

Anything wrong in my logic?
Yes your logic is flawed becuase in your case you would be needing to satisfy 888 (AB=84(A=8)) or 777(AB=74(A=7))

The question is asking for two, two digit postive integers when added together equal a 3 digit positve integer where all three digits are the same(this is your A value). Only option is AAA= 111
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by piyush_nitt » Wed Jan 14, 2009 7:56 pm
Mr2Bits wrote:
piyush_nitt wrote:
Mr2Bits wrote:
adilka wrote:Correct folks. OA is 9, E
Answer is 9 (D) was no other value satisfies AAA having to equal 111.

How about

84 + 27

74 + 37

Above eqn , equates to 111


Got it ..Thanks !

Missed that part.

Anything wrong in my logic?
Yes your logic is flawed becuase in your case you would be needing to satisfy 888 (AB=84(A=8)) or 777(AB=74(A=7))

The question is asking for two, two digit postive integers when added together equal a 3 digit positve integer where all three digits are the same(this is your A value). Only option is AAA= 111
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