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gmattester
- Master | Next Rank: 500 Posts
- Posts: 172
- Joined: Wed Oct 31, 2007 11:21 am
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If x dollars is invested at 10 percent for one year and
y dollars is invested at 8 percent for one year, the
annual income from the 10 percent investment will
exceed the annual income from the 8 percent
investment by $56. If $2,000 is the total amount
invested, how much is invested at 8 percent?
(A) $280
(B) $800
(C) $892
(D) $1,108
(E) $1,200
Here is my strategy but I am not getting answer
P1-P2=56------------1
P1=x+x/10=11x/10
P2=y+8y/100=108y/100
x+ y=2000---------------2
From 1 and 2 find value of x
y dollars is invested at 8 percent for one year, the
annual income from the 10 percent investment will
exceed the annual income from the 8 percent
investment by $56. If $2,000 is the total amount
invested, how much is invested at 8 percent?
(A) $280
(B) $800
(C) $892
(D) $1,108
(E) $1,200
Here is my strategy but I am not getting answer
P1-P2=56------------1
P1=x+x/10=11x/10
P2=y+8y/100=108y/100
x+ y=2000---------------2
From 1 and 2 find value of x















