What is the distance?

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rrobiinn: Junior | Next Rank: 30 Posts; Posts: 24; Joined: Tue Mar 06, 2012 5:35 am

by rrobiinn » Wed Sep 19, 2012 10:56 pm

If a boy takes as much time in running 10m as a car takes in covering 25m, the distance covered by the boy during the time the car covers 1km, is what?

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Source: Beat The GMAT — Problem Solving | Wed Sep 19, 2012 10:56 pm

rrobiinn: Junior | Next Rank: 30 Posts; Posts: 24; Joined: Tue Mar 06, 2012 5:35 am

by rrobiinn » Wed Sep 19, 2012 11:05 pm

rrobiinn wrote:If a boy takes as much time in running 10m as a car takes in covering 25m, the distance covered by the boy during the time the car covers 1km, is what?

.

I solved it just now. Couldn't find the post delete button.

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KapilKapoor: Junior | Next Rank: 30 Posts; Posts: 22; Joined: Sat Aug 25, 2012 11:50 pm; Thanked: 2 times

by KapilKapoor » Wed Sep 19, 2012 11:07 pm

Hi,

Assume speed of boy = b
Speed of car = c

time = distance/speed = 10/b = 25/c
=> b/c= 10/25

distance by b = time taken by c for travelling 1000 mtr * speed of b
time by c = 1000/c

Distance by b = 1000/c*b
1000*10/25 = 400 mtr

By the way what are the options.

Regards,
Kapil

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Jim@StratusPrep: MBA Admissions Consultant; Posts: 2279; Joined: Fri Nov 11, 2011 7:51 amFollowed by: 266 members; Location: New York; Thanked: 660 times; GMAT Score:770

by Jim@StratusPrep » Thu Sep 20, 2012 7:42 am

Just divide 10 by 25 to get .4m

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Brent@GMATPrepNow: GMAT Instructor; Posts: 16207; Joined: Mon Dec 08, 2008 6:26 pmFollowed by: 1268 members; Location: Vancouver, BC; Thanked: 5254 times; GMAT Score:770

by Brent@GMATPrepNow » Thu Sep 20, 2012 9:17 am

rrobiinn wrote:If a boy takes as much time in running 10m as a car takes in covering 25m, the distance covered by the boy during the time the car covers 1km, is what?

Whenever you can rephrase a question to read, "For every X something else happens", we can typically solve the question using equivalent ratios.

Here, we have "For every 10m a boy travels, a car travel 25m"
Here, we're comparing the boy's distance to the car's distance.
We want to know the number of meters the boy travels during the time the car travels 1km (1000m).

Let B = the number of meters the boy travels during the time the car travels 1000m

Equivalent ratios
boy's distance/car's distance: __ 10/25 = B/1000

To solve, cross multiply to get: 25B = (10)(1000)
Solve for B to get B=400m

Cheers,
Brent

Brent Hanneson - Creator of GMATPrepNow.com

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