1*2*3=6
hence its A....just my view.
3 consecutives
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beatthegmat.garry
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Among any 3 consecutive integers you will find either 2 numbers one of them a multiple of 2 and the other a multiple of 3 or one number which is multiple of 6. Hence when you multiple 3 consecutive numbers the product will be a multiple of 6.
From the above list 116 is the only number which is not a multiple of 6.
Hence the answer is C.
Thanks !
From the above list 116 is the only number which is not a multiple of 6.
Hence the answer is C.
Thanks !
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MarkMeier20
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B,C,D and E could not be a value of r. 6 could be a value of r.If p is a positive integer and
r = p(p + 1) (p + 2), then which of the
following could not be a value of r?
A. 6
B. 36
C. 116
D. 156
E. 180
Hi!beatthegmat.garry wrote:Among any 3 consecutive integers you will find either 2 numbers one of them a multiple of 2 and the other a multiple of 3 or one number which is multiple of 6. Hence when you multiple 3 consecutive numbers the product will be a multiple of 6.
From the above list 116 is the only number which is not a multiple of 6.
Hence the answer is C.
Thanks !
Thank you for your explanation. Can you please tell me what are the three consecutive numbers that give 36 when multiplied.
