The events A and B are independent. The probability that event A occurs is 0.6, and the probability that at least one of the events A or B occurs is 0.94. What is the probability that event B occurs?
(A) 0.34
(B) 0.65
(C) 0.72
(D) 0.76
(E) 0.85
Looking for a formula to deal with this one!
Probability of A or B
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Atleast one event = 1 - ( not P(A) AND not P(B)) = 0.94GmatKiss wrote:The events A and B are independent. The probability that event A occurs is 0.6, and the probability that at least one of the events A or B occurs is 0.94. What is the probability that event B occurs?
(A) 0.34
(B) 0.65
(C) 0.72
(D) 0.76
(E) 0.85
Looking for a formula to deal with this one!
=> 1 - ( (1 - 0.6) * ( 1 - B) ) = 0.94
1 - 0.4(1-B) = 0.94
0.4(1 - B) = 0.06
1 - B = 6/40 => B = 34/40 = 0.85
Hence E!