A small company employs 3 men and 5 women. If a team of 4 employees is to be randomly selected to organize the company retreat, what is the probability that the team will have exactly 2 women?
1/14
1/7
2/7
3/7
1/2
solution : total people can be selected in 8C4 ways => 70
The 3 women can be selected in : 5C3 ways => 10
The 2 men can be selected in : 3C2 ways => 3
Hence total ways of selecting : 3*10 = 30
Hence Probability : 30/70 = 3/7.
Is there a different way to solving this problem ? Can anyone tell me what is the best way to solve this problem ?
1/14
1/7
2/7
3/7
1/2
solution : total people can be selected in 8C4 ways => 70
The 3 women can be selected in : 5C3 ways => 10
The 2 men can be selected in : 3C2 ways => 3
Hence total ways of selecting : 3*10 = 30
Hence Probability : 30/70 = 3/7.
Is there a different way to solving this problem ? Can anyone tell me what is the best way to solve this problem ?
