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Source: — Data Sufficiency |
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by acecoolan » Sat Dec 27, 2008 10:56 am
Firstly don't assume w to be a integer since its not mentioned.

So if u take w = -1.2

Statement 1
w + 2 = -1.2 + 2 = 0.8 > 0

Statement 2
w^2 = (-1.2)^2 = 1.44 > 1

So clearly w can be < 1.

Hence E)
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by cramya » Sat Dec 27, 2008 11:04 am
Stm I

w > -2

INSUFF

Stmt II

|w| > 1

w> 1 or w < -1

INSUFF

Together

w> -2

w^2 > 1

Take w = -1.5 > -2 w^2 > 1 NO
Take w = 2 2>-2 w^2>1 YES

Choose E)
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by vscid » Tue Dec 30, 2008 9:21 pm
As usual with the GMAT trap, w could be a fraction as well as integer.
Clear E.
The GMAT is indeed adaptable. Whenever I answer RC, it proficiently 'adapts' itself to mark my 'right' answer 'wrong'.
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by vivek.kapoor83 » Wed Dec 31, 2008 2:20 am
cramya wrote:Stmt II

|w| > 1

w> 1 or w < -1

INSUFF
cramya,
i hv ques here.
w^2 >1
then w>1 is ok
and w>-1 but as per u, it wil be w <-1
howcm..cn u explain.
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by cramya » Wed Dec 31, 2008 10:57 am
cramya,
i hv ques here.
w^2 >1
then w>1 is ok
and w>-1 but as per u, it wil be w <-1
howcm..cn u explain.
w^2 > 1

|w| > 1

case 1(w positive):

w > 1

case 2: (w negative)

-w > 1

Divide by -1 inequality reverses

w < -1

Hope this helps!

Regards,
CR
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Re: W's.........GMAT PREP (Download off new website)

by logitech » Wed Dec 31, 2008 1:47 pm
(1) w+2>0


-2-----------------------> INSUF


(2) w^2>1

<--------------- - 1 + 1 -----------------------> INSUF

Together

-2 ----- -1 + 1------------------------> It still can be between -2 and - 1

E
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Re: W's.........GMAT PREP (Download off new website)

by iamcste » Wed Dec 31, 2008 1:52 pm
logitech wrote:(1) w+2>0


-2-----------------------> INSUF


(2) w^2>1

<--------------- - 1 + 1 -----------------------> INSUF

Together

-2 ----- -1 + 1------------------------> It still can be between -2 and - 1

E

yeah, its best to visualize inequalities on the number line, wherever possible
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by TNgri » Tue Feb 17, 2009 8:54 pm
I thought that answer would be B. The question is asking whether w greater than 1?
If we state that the w will be less than 1, it is an answer to the question. Is it not?
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by [email protected] » Sun May 24, 2009 9:58 pm
this question only fools you once. Then from here on you will always look for the integers at the top.

Nate
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by ironsferri » Tue Jun 29, 2010 3:21 pm
HI All!

still not sure why I get confused on the feasability of stmt 2.
It says x>1 and x<1. So x is >1, correct? If so stmts 2 should be correct.

Is this what I'm missing?? : stmt 2 is saying instead x>1 OR x<1

Thanks![/i]
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by kvcpk » Tue Jun 29, 2010 6:25 pm
ironsferri wrote:HI All!

still not sure why I get confused on the feasability of stmt 2.
It says x>1 and x<1. So x is >1, correct? If so stmts 2 should be correct.

Is this what I'm missing?? : stmt 2 is saying instead x>1 OR x<1

Thanks![/i]
stm2 is saying x>1 OR x<-1

So we are not sure if the valuewould be >1

Hope this helps!!
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by Testluv » Tue Jun 29, 2010 7:03 pm
Hi ironsferri,

kvcpk is correct.

Whenever you have two inequalities that can't mutually coexist (ie, w can't be greater than 1 and less than -1 at the same time), then you have alternative inequalities rather than joint inequalities.

So, how can w^2 be greater than 1? Only if w^2 is greater than 1.

And w^2 will be greater than 1 when |w| is greater than 1. So, either w is greater than 1 OR less than -1. (It is very helpful to plot this out on the number line).
Kaplan Teacher in Toronto
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