BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
Live EA class + 6 months of EA OnDemand
  • Expert-led weekly online sessions
  • EA Masterclass access between classes
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

130-point score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Probability - black balls and white balls

Expert replies
by Brent@GMATPrepNow » Sun Dec 21, 2008 11:15 am
An urn is filled with black balls and white balls only. There are 45 balls in total. If the probability of randomly drawing a white ball is 4/5, how many white balls must be added to the urn so that the probability of randomly drawing a white ball is 7/8?

To prevent "plugging and chugging," I'll leave this as an open-ended question. :D
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion
Source: — Problem Solving |

Brent Hanneson wrote:An urn is filled with black balls and white balls only. There are 45 balls in total. If the probability of randomly drawing a white ball is 4/5, how many white balls must be added to the urn so that the probability of randomly drawing a white ball is 7/8?

To prevent "plugging and chugging," I'll leave this as an open-ended question. :D
White balls = W

W/45 = 4/5

W = 36

Let x be the number of white balls to be added

36+x / 45 + x = 7/8

288 + 8x = 315 + 7x

x = 27

Hence, 27 balls must be added.

OA?
No rest for the Wicked....
Join the discussion

by Brent@GMATPrepNow » Sun Dec 21, 2008 12:50 pm
The answer is 27 - great work
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion

by vishubn » Sun Dec 21, 2008 11:57 pm
B and WHite balss

B+W=45

4/5=F/45

36 white balls .. and 9 balck balls

so the probality !!

7/8=36+x/45+x

solve for x 27 balss must be added
KILL !! DIE !! or BEAT my FEAR !!! de@D END!!
Join the discussion

by ronniecoleman » Mon Dec 22, 2008 1:15 am
An urn is filled with black balls and white balls only. There are 45 balls in total. If the probability of randomly drawing a white ball is 4/5,
how many white balls must be added to the urn so that
the probability of randomly drawing a white ball is 7/8?



x + y = 45

x/ x+y = 4/5

x = 36
y = 9

7/8 = 36+k / 45+ k

k = 27

hence 27 balls have to be added
Admission champion, Hauz khaz
011-27565856
Join the discussion

by Mozartain » Mon Dec 22, 2008 10:08 am
For the sake of simplified calculation, we can set up the ratio for white ball to black ball -
(36+x)/9 = 7/1
Join the discussion

by txeconomist » Tue Dec 23, 2008 12:47 pm
Out of curiosity, what level do you all think this is?
Join the discussion

by Mozartain » Tue Dec 23, 2008 7:11 pm
txeconomist wrote:Out of curiosity, what level do you all think this is?
On a scale of 1 to 10 with 10 being the hardest level, I'd say it's 7. But I'm not an expert.
Join the discussion