Probability - 10 marbles

This topic has expert replies
User avatar
Legendary Member
Posts: 540
Joined: Sat Dec 20, 2008 7:24 pm
Thanked: 37 times
Followed by:6 members

by navami » Thu Aug 25, 2011 2:33 am
Good Question
This time no looking back!!!
Navami

Newbie | Next Rank: 10 Posts
Posts: 1
Joined: Wed Jun 01, 2011 10:15 am

by dushyantsahni » Wed Aug 31, 2011 11:32 pm
Two Possible ways in which the outcome is achieved : WWWWWBBBBB & BBBBBWWWWW

So,
To Select white marble from 10 marbles, probablility for 1st girl is 5/10
To Select white marble from 9 marbles, probablility for 2nd girl is 4/9
To Select white marble from 8 marbles, probablility for 3rd girl is 3/8
To Select white marble from 7 marbles, probablility for 4th girl is 2/7
To Select white marble from 6 marbles, probablility for 5th girl is 1/6

Therefore
Probablity when white is chosen by all 5 girls is
5/10 * 4/9 * 3/8 * 2/7 * 1/6

Probablity when black is chosen by all 5 girls is
5/10 * 4/9 * 3/8 * 2/7 * 1/6

Ans = 1/126

User avatar
Legendary Member
Posts: 540
Joined: Sat Dec 20, 2008 7:24 pm
Thanked: 37 times
Followed by:6 members

by navami » Thu Sep 08, 2011 12:23 pm
1/126
This time no looking back!!!
Navami

Newbie | Next Rank: 10 Posts
Posts: 4
Joined: Sun Sep 11, 2011 4:08 am

by soubhg » Wed Sep 14, 2011 5:46 am
My logic:
Required number of cases (R)= number of ways selecting W-marble or B-marble
= 10C5*2

To find total number of cases (T):
5 girls and 5 boys are arranged in 10 chairs . Number of ways = 10|/(5|*5|)= 10C2.
Now 5 W-marbles and 5 B-marbles are arrnaged in 10 chairs. No. of ways = 10|/(5|*5|) = 10C2.

Hence reqd. prob. = R/T = 2/(5C2) = 1/126.

This is how I formulated the problem.

Comments from GMAT instructors are highly solicited.

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pm
Location: Vancouver, BC
Thanked: 5254 times
Followed by:1268 members
GMAT Score:770

by Brent@GMATPrepNow » Wed Sep 14, 2011 8:10 am
Brent@GMATPrepNow wrote:Source: Beat The GMAT Practice Questions

A bag contains 5 white marbles and 5 black marbles. If each of 5 girls and 5 boys randomly selects and keeps a marble, what is the probability that all of the girls select the same colored marble?
a) 1/126
b) 1/120
c) 1/24
d) 4/25
e) 1/2
I thought I'd re-post the question here so people don't have to keep going back to see it.
Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pm
Location: Vancouver, BC
Thanked: 5254 times
Followed by:1268 members
GMAT Score:770

by Brent@GMATPrepNow » Wed Sep 14, 2011 8:35 am
soubhg wrote:My logic:
Required number of cases (R)= number of ways selecting W-marble or B-marble
= 10C5*2

To find total number of cases (T):
5 girls and 5 boys are arranged in 10 chairs . Number of ways = 10|/(5|*5|)= 10C2.
Now 5 W-marbles and 5 B-marbles are arrnaged in 10 chairs. No. of ways = 10|/(5|*5|) = 10C2.

Hence reqd. prob. = R/T = 2/(5C2) = 1/126.

This is how I formulated the problem.

Comments from GMAT instructors are highly solicited.
I'm not sure if I follow this solution. It would help me assess your solution if you provided a little more text for each step. For example, I'm not really sure what you are doing when you arrange the children and marbles in the chairs.

This could very well be a good approach, I just can't tell what you are doing exactly.

Also, at the end, you write: probability = R/T = 2/(5C2) = 1/126
But, 5C2 = 10, so 2/(5C2) is actually equal to 2/20 (or 1/10), not 1/126

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image

Master | Next Rank: 500 Posts
Posts: 197
Joined: Thu Sep 15, 2011 10:22 am
Thanked: 6 times
Followed by:2 members

by parul9 » Sun Sep 18, 2011 11:13 am
I thought a lot. Probability is not my strong point.
But I got the answer!! Yayy! :D :D

It's A!

There can be 2 cases.
Case1: Girls choose white
P(1st Girl) = 5/10 = 1/2
P(2nd Girl) = 4/9
P(3rd Girl) = 3/7
P(4ht Girl) = 2/6 = 1/3
P(5th Girl) = 1

P (all white) = 1/2*4/9*3/7*1/3*1

Case 2: Girls Choose Black

P(1st Girl) = 5/10 = 1/2
P(2nd Girl) = 4/9
P(3rd Girl) = 3/7
P(4ht Girl) = 2/6 = 1/3
P(5th Girl) = 1

P (all Black) = 1/2*4/9*3/7*1/3*1

Therefore, P(Girls choose same color) = P(all white) + P(all black)
= 1/126

So the answer is A!

User avatar
Newbie | Next Rank: 10 Posts
Posts: 1
Joined: Mon Sep 26, 2011 7:47 pm

by Shawnm » Mon Sep 26, 2011 7:50 pm
To me, the easiest way to solve this is just with the # good outcomes / # total outcomes

# good outcomes = the number of ways to choose all white or all black balls = 2 x 5!

# total outcomes = the number of ways to choose 5 balls from 10 balls = 10 x 9 x 8 x 7 x 6

= 1 / 126

User avatar
Senior | Next Rank: 100 Posts
Posts: 32
Joined: Mon Sep 26, 2011 6:34 pm

by way2ashish » Wed Sep 28, 2011 5:55 pm
Good one. I could not figure out initially but got the answer from the posts
Nice learning

Senior | Next Rank: 100 Posts
Posts: 62
Joined: Mon Aug 02, 2010 3:25 pm
Thanked: 3 times

by Taniuca » Fri Sep 30, 2011 5:09 am
Could someone explain to me, why the prob of being a woman is not included in the calculation?
I would thought the prob should be
(prob woman)*prob of white ball
5/10*5/10+4/9*4/9+3/8*3/8+2/7+2/7+1/6*1/6

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pm
Location: Vancouver, BC
Thanked: 5254 times
Followed by:1268 members
GMAT Score:770

by Brent@GMATPrepNow » Fri Sep 30, 2011 5:21 am
Taniuca wrote:Could someone explain to me, why the prob of being a woman is not included in the calculation?
I would thought the prob should be
(prob woman)*prob of white ball
5/10*5/10+4/9*4/9+3/8*3/8+2/7+2/7+1/6*1/6
To answer the question, we need only determine the probability that the men all receive the same colored marble, since this implies that the women all receive the same colored marble as well.

Consider this example: A box contains a white chip and a black chip. You randomly select a chip and I select the remaining chip.
What is the probability that you get the white chip and I get the black chip?
Notice that the second part (Brent gets the black chip) is somewhat redundant here. If you select the white chip then my selecting the black chip is guaranteed.
So, we could reword the question to simply read "What is the probability that you get the white chip," since the second part (Brent gets the black chip) is implied.

The same goes for the original question; once the men all receive the same colored marble, the women are guaranteed to receive the same colored marble as well.

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image

User avatar
Master | Next Rank: 500 Posts
Posts: 183
Joined: Wed Sep 21, 2011 7:06 am
Location: Washington, DC
Thanked: 6 times
Followed by:2 members
GMAT Score:500

by Rastis » Mon Oct 03, 2011 7:57 am
Can someone please work out the math? I'm not coming up with the answer when i multiply the fractions out.

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pm
Location: Vancouver, BC
Thanked: 5254 times
Followed by:1268 members
GMAT Score:770

by Brent@GMATPrepNow » Mon Oct 03, 2011 8:05 am
Rastis wrote:Can someone please work out the math? I'm not coming up with the answer when i multiply the fractions out.
The calculations you are referring to depend on which solution you are referring to.

My solution requires us to find this product: 1 x 4/9 x 3/8 x 2/7 x 1/6 x 1

Notice that we can simplify terms as we go.

1 x 4/9 x 3/8 x 2/7 x 1/6 x 1 - the 4 and 8 can be simplified to get:
1 x 1/9 x 3/2 x 2/7 x 1/6 x 1

From here, we can simplify the 3 and 9 in 1 x 1/9 x 3/2 x 2/7 x 1/6 x 1 to get:
1 x 1/3 x 1/2 x 2/7 x 1/6 x 1

Finally, we can simplify the 2 and 2 in 1 x 1/3 x 1/2 x 2/7 x 1/6 x 1 to get:
1 x 1/3 x 1/1 x 1/7 x 1/6 x 1, which equals 1/126

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image

User avatar
Legendary Member
Posts: 588
Joined: Sun Oct 16, 2011 9:42 am
Location: New Delhi, India
Thanked: 130 times
Followed by:9 members
GMAT Score:720

by rijul007 » Wed Oct 19, 2011 10:42 am
Total no of ways of arranging 10 marbles amongst 5 boys and 5 girls =>> 10!/(5!*5!) => 252

No of ways of arranging marbles such that all the girls recieve the same colored marbles => 2(either black or white)

Probability => 2/252 => 1/126

User avatar
Legendary Member
Posts: 588
Joined: Sun Oct 16, 2011 9:42 am
Location: New Delhi, India
Thanked: 130 times
Followed by:9 members
GMAT Score:720

by rijul007 » Wed Oct 19, 2011 12:33 pm
Brent@GMATPrepNow wrote:
soubhg wrote:My logic:
Required number of cases (R)= number of ways selecting W-marble or B-marble
= 10C5*2

To find total number of cases (T):
5 girls and 5 boys are arranged in 10 chairs . Number of ways = 10|/(5|*5|)= 10C2.
Now 5 W-marbles and 5 B-marbles are arrnaged in 10 chairs. No. of ways = 10|/(5|*5|) = 10C2.

Hence reqd. prob. = R/T = 2/(5C2) = 1/126.

This is how I formulated the problem.

Comments from GMAT instructors are highly solicited.
I'm not sure if I follow this solution. It would help me assess your solution if you provided a little more text for each step. For example, I'm not really sure what you are doing when you arrange the children and marbles in the chairs.

This could very well be a good approach, I just can't tell what you are doing exactly.

Also, at the end, you write: probability = R/T = 2/(5C2) = 1/126
But, 5C2 = 10, so 2/(5C2) is actually equal to 2/20 (or 1/10), not 1/126

Cheers,
Brent

the logic used by soubhg is correct, though he has made sm mistakes in the solution....

Let us first place the children on 10 chairs and arrange the ten marbles among the chairs such that each kid gets a marble...
so the total no of arangements that can be made is ,T=10C5 => 252
No of ways of arranging marbles such that all the girls recieve the same colored marbles,R => 2(either all black or all white)
Probability=R/T=>2/252 => 1/126

at the end of his solution, he appears to have made a typo... i guess what he meant was 10C5 and not 5C2