Probability - 10 marbles
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dushyantsahni
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Two Possible ways in which the outcome is achieved : WWWWWBBBBB & BBBBBWWWWW
So,
To Select white marble from 10 marbles, probablility for 1st girl is 5/10
To Select white marble from 9 marbles, probablility for 2nd girl is 4/9
To Select white marble from 8 marbles, probablility for 3rd girl is 3/8
To Select white marble from 7 marbles, probablility for 4th girl is 2/7
To Select white marble from 6 marbles, probablility for 5th girl is 1/6
Therefore
Probablity when white is chosen by all 5 girls is
5/10 * 4/9 * 3/8 * 2/7 * 1/6
Probablity when black is chosen by all 5 girls is
5/10 * 4/9 * 3/8 * 2/7 * 1/6
Ans = 1/126
So,
To Select white marble from 10 marbles, probablility for 1st girl is 5/10
To Select white marble from 9 marbles, probablility for 2nd girl is 4/9
To Select white marble from 8 marbles, probablility for 3rd girl is 3/8
To Select white marble from 7 marbles, probablility for 4th girl is 2/7
To Select white marble from 6 marbles, probablility for 5th girl is 1/6
Therefore
Probablity when white is chosen by all 5 girls is
5/10 * 4/9 * 3/8 * 2/7 * 1/6
Probablity when black is chosen by all 5 girls is
5/10 * 4/9 * 3/8 * 2/7 * 1/6
Ans = 1/126
My logic:
Required number of cases (R)= number of ways selecting W-marble or B-marble
= 10C5*2
To find total number of cases (T):
5 girls and 5 boys are arranged in 10 chairs . Number of ways = 10|/(5|*5|)= 10C2.
Now 5 W-marbles and 5 B-marbles are arrnaged in 10 chairs. No. of ways = 10|/(5|*5|) = 10C2.
Hence reqd. prob. = R/T = 2/(5C2) = 1/126.
This is how I formulated the problem.
Comments from GMAT instructors are highly solicited.
Required number of cases (R)= number of ways selecting W-marble or B-marble
= 10C5*2
To find total number of cases (T):
5 girls and 5 boys are arranged in 10 chairs . Number of ways = 10|/(5|*5|)= 10C2.
Now 5 W-marbles and 5 B-marbles are arrnaged in 10 chairs. No. of ways = 10|/(5|*5|) = 10C2.
Hence reqd. prob. = R/T = 2/(5C2) = 1/126.
This is how I formulated the problem.
Comments from GMAT instructors are highly solicited.
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- Brent@GMATPrepNow
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I thought I'd re-post the question here so people don't have to keep going back to see it.Brent@GMATPrepNow wrote:Source: Beat The GMAT Practice Questions
A bag contains 5 white marbles and 5 black marbles. If each of 5 girls and 5 boys randomly selects and keeps a marble, what is the probability that all of the girls select the same colored marble?
a) 1/126
b) 1/120
c) 1/24
d) 4/25
e) 1/2
Cheers,
Brent
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I'm not sure if I follow this solution. It would help me assess your solution if you provided a little more text for each step. For example, I'm not really sure what you are doing when you arrange the children and marbles in the chairs.soubhg wrote:My logic:
Required number of cases (R)= number of ways selecting W-marble or B-marble
= 10C5*2
To find total number of cases (T):
5 girls and 5 boys are arranged in 10 chairs . Number of ways = 10|/(5|*5|)= 10C2.
Now 5 W-marbles and 5 B-marbles are arrnaged in 10 chairs. No. of ways = 10|/(5|*5|) = 10C2.
Hence reqd. prob. = R/T = 2/(5C2) = 1/126.
This is how I formulated the problem.
Comments from GMAT instructors are highly solicited.
This could very well be a good approach, I just can't tell what you are doing exactly.
Also, at the end, you write: probability = R/T = 2/(5C2) = 1/126
But, 5C2 = 10, so 2/(5C2) is actually equal to 2/20 (or 1/10), not 1/126
Cheers,
Brent
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parul9
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I thought a lot. Probability is not my strong point.
But I got the answer!! Yayy!

It's A!
There can be 2 cases.
Case1: Girls choose white
P(1st Girl) = 5/10 = 1/2
P(2nd Girl) = 4/9
P(3rd Girl) = 3/7
P(4ht Girl) = 2/6 = 1/3
P(5th Girl) = 1
P (all white) = 1/2*4/9*3/7*1/3*1
Case 2: Girls Choose Black
P(1st Girl) = 5/10 = 1/2
P(2nd Girl) = 4/9
P(3rd Girl) = 3/7
P(4ht Girl) = 2/6 = 1/3
P(5th Girl) = 1
P (all Black) = 1/2*4/9*3/7*1/3*1
Therefore, P(Girls choose same color) = P(all white) + P(all black)
= 1/126
So the answer is A!
But I got the answer!! Yayy!
It's A!
There can be 2 cases.
Case1: Girls choose white
P(1st Girl) = 5/10 = 1/2
P(2nd Girl) = 4/9
P(3rd Girl) = 3/7
P(4ht Girl) = 2/6 = 1/3
P(5th Girl) = 1
P (all white) = 1/2*4/9*3/7*1/3*1
Case 2: Girls Choose Black
P(1st Girl) = 5/10 = 1/2
P(2nd Girl) = 4/9
P(3rd Girl) = 3/7
P(4ht Girl) = 2/6 = 1/3
P(5th Girl) = 1
P (all Black) = 1/2*4/9*3/7*1/3*1
Therefore, P(Girls choose same color) = P(all white) + P(all black)
= 1/126
So the answer is A!
To me, the easiest way to solve this is just with the # good outcomes / # total outcomes
# good outcomes = the number of ways to choose all white or all black balls = 2 x 5!
# total outcomes = the number of ways to choose 5 balls from 10 balls = 10 x 9 x 8 x 7 x 6
= 1 / 126
# good outcomes = the number of ways to choose all white or all black balls = 2 x 5!
# total outcomes = the number of ways to choose 5 balls from 10 balls = 10 x 9 x 8 x 7 x 6
= 1 / 126
- way2ashish
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Could someone explain to me, why the prob of being a woman is not included in the calculation?
I would thought the prob should be
(prob woman)*prob of white ball
5/10*5/10+4/9*4/9+3/8*3/8+2/7+2/7+1/6*1/6
I would thought the prob should be
(prob woman)*prob of white ball
5/10*5/10+4/9*4/9+3/8*3/8+2/7+2/7+1/6*1/6
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To answer the question, we need only determine the probability that the men all receive the same colored marble, since this implies that the women all receive the same colored marble as well.Taniuca wrote:Could someone explain to me, why the prob of being a woman is not included in the calculation?
I would thought the prob should be
(prob woman)*prob of white ball
5/10*5/10+4/9*4/9+3/8*3/8+2/7+2/7+1/6*1/6
Consider this example: A box contains a white chip and a black chip. You randomly select a chip and I select the remaining chip.
What is the probability that you get the white chip and I get the black chip?
Notice that the second part (Brent gets the black chip) is somewhat redundant here. If you select the white chip then my selecting the black chip is guaranteed.
So, we could reword the question to simply read "What is the probability that you get the white chip," since the second part (Brent gets the black chip) is implied.
The same goes for the original question; once the men all receive the same colored marble, the women are guaranteed to receive the same colored marble as well.
Cheers,
Brent
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The calculations you are referring to depend on which solution you are referring to.Rastis wrote:Can someone please work out the math? I'm not coming up with the answer when i multiply the fractions out.
My solution requires us to find this product: 1 x 4/9 x 3/8 x 2/7 x 1/6 x 1
Notice that we can simplify terms as we go.
1 x 4/9 x 3/8 x 2/7 x 1/6 x 1 - the 4 and 8 can be simplified to get:
1 x 1/9 x 3/2 x 2/7 x 1/6 x 1
From here, we can simplify the 3 and 9 in 1 x 1/9 x 3/2 x 2/7 x 1/6 x 1 to get:
1 x 1/3 x 1/2 x 2/7 x 1/6 x 1
Finally, we can simplify the 2 and 2 in 1 x 1/3 x 1/2 x 2/7 x 1/6 x 1 to get:
1 x 1/3 x 1/1 x 1/7 x 1/6 x 1, which equals 1/126
Cheers,
Brent
- rijul007
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Total no of ways of arranging 10 marbles amongst 5 boys and 5 girls =>> 10!/(5!*5!) => 252
No of ways of arranging marbles such that all the girls recieve the same colored marbles => 2(either black or white)
Probability => 2/252 => 1/126
No of ways of arranging marbles such that all the girls recieve the same colored marbles => 2(either black or white)
Probability => 2/252 => 1/126
- rijul007
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Brent@GMATPrepNow wrote:I'm not sure if I follow this solution. It would help me assess your solution if you provided a little more text for each step. For example, I'm not really sure what you are doing when you arrange the children and marbles in the chairs.soubhg wrote:My logic:
Required number of cases (R)= number of ways selecting W-marble or B-marble
= 10C5*2
To find total number of cases (T):
5 girls and 5 boys are arranged in 10 chairs . Number of ways = 10|/(5|*5|)= 10C2.
Now 5 W-marbles and 5 B-marbles are arrnaged in 10 chairs. No. of ways = 10|/(5|*5|) = 10C2.
Hence reqd. prob. = R/T = 2/(5C2) = 1/126.
This is how I formulated the problem.
Comments from GMAT instructors are highly solicited.
This could very well be a good approach, I just can't tell what you are doing exactly.
Also, at the end, you write: probability = R/T = 2/(5C2) = 1/126
But, 5C2 = 10, so 2/(5C2) is actually equal to 2/20 (or 1/10), not 1/126
Cheers,
Brent
the logic used by soubhg is correct, though he has made sm mistakes in the solution....
Let us first place the children on 10 chairs and arrange the ten marbles among the chairs such that each kid gets a marble...
so the total no of arangements that can be made is ,T=10C5 => 252
No of ways of arranging marbles such that all the girls recieve the same colored marbles,R => 2(either all black or all white)
Probability=R/T=>2/252 => 1/126
at the end of his solution, he appears to have made a typo... i guess what he meant was 10C5 and not 5C2













