(365*3) +1 = 1096
If today is thursday, when i go 7 days behind today it would be a wednesday.
now 1092 is the nearest multiple of 7.
so 1092 days behind 20th sept 1990 would be wednesday and 1096 days behind would be SATURDAY
day..
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arora007
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Rahul@gurome
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The question has some problem with the option.
The answer is indeed Saturday.
Though the solution provided by arora007 is correct and elegant, I want to add some thumb rules for these types of problems which some of you may find useful.
A 30 day month = 30 days = (7*4 + 2) days --> 2 extra days
A 31 day month = 31 days = (7*4 + 3) days --> 3 extra days
A normal year = 365 days = (7*52 + 1) days --> 1 extra day
A leap year = 366 days = (7*52 + 2) days --> 2 extra days
In this case, the difference is equal to 2 normal years, 1 leap year and 1 day. Which is equivalent to (2*1 + 1*2 + 1) = 5 extra days. Hence we have to go 5 days back from a Thursday, which is indeed Saturday.
The answer is indeed Saturday.
Though the solution provided by arora007 is correct and elegant, I want to add some thumb rules for these types of problems which some of you may find useful.
A 30 day month = 30 days = (7*4 + 2) days --> 2 extra days
A 31 day month = 31 days = (7*4 + 3) days --> 3 extra days
A normal year = 365 days = (7*52 + 1) days --> 1 extra day
A leap year = 366 days = (7*52 + 2) days --> 2 extra days
In this case, the difference is equal to 2 normal years, 1 leap year and 1 day. Which is equivalent to (2*1 + 1*2 + 1) = 5 extra days. Hence we have to go 5 days back from a Thursday, which is indeed Saturday.
Rahul Lakhani
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Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)
