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by maihuna » Mon Apr 20, 2009 7:19 am
the sum of three prime nos is 100 one of them exceeds the other by 36 then one of the no is:
1. 3 : sorry edited
2. 7
3. 19
4.41
5. 67
Last edited by maihuna on Mon Apr 20, 2009 9:15 am, edited 1 time in total.
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by rossmj » Mon Apr 20, 2009 7:24 am
A. 2

There is only one even prime number and the sum of three odds will never be even, so two numbers must be odd and one number must be even.
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by moutar » Mon Apr 20, 2009 10:48 am
a + b + c = 100

As said above one of the prime number needs to be 2.

2 + b + c = 100

b + c = 98 ... (1)

We know the difference between b and c is 36.

c - b = 36 ... (2)


(1) - (2) ... 2b = 62 => b = 31

c = 36 + 31 = 67 - Answer: 5
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by dumb.doofus » Mon Apr 20, 2009 11:09 am
E

numbers are 2, 31 and 67

can get that by solving the below two equations:
a+b = 98
a-b = 36
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