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Prime factors/number properties

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by BTGmoderatorRO » Sat Oct 28, 2017 3:49 am
If {x} is the product of all even integers from 1 to x inclusive, what is the greatest prime factor of {22} + {20}?
A) 23
B) 20
C) 11
D) 5
E) 2
OA is a
What is the correct answer here how do you arrive at it? please help me out.
Thanks
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Source: — Problem Solving |

by EconomistGMATTutor » Sat Oct 28, 2017 1:54 pm
If {x} is the product of all even integers from 1 to x inclusive, what is the greatest prime factor of {22} + {20}?
A) 23
B) 20
C) 11
D) 5
E) 2
OA is a
What is the correct answer here how do you arrive at it? please help me out.
Thanks
Hi Roland2rule,
Let's take a look at your question.

Since, {x} is the product of all even integers from 1 to x inclusive, therefore we can write {22} as,
$$\left\{22\right\}=22\times20\times18\times16\times...\times2$$
Similarly {20} can be written in product form as:
$$\left\{20\right\}=20\times18\times16\times...\times2$$

Now we are asked to find the greatest prime factor of {22}+{20}. For this purpose let's find the sum first.
$$\left\{22\right\}+\left\{20\right\}=\left(22\times20\times18\times16\times...\times2\right)+\left(20\times18\times16\times...\times2\right)$$

Factor out (20 x 18 x 16 x .. x 2), we get
$$\left\{22\right\}+\left\{20\right\}=\left(20\times18\times16\times...\times2\right)\left(22+1\right)$$
$$\left\{22\right\}+\left\{20\right\}=\left(20\times18\times16\times...\times2\right)23$$

Now we can see all the factors of {22}+{20}, Except 23 which is a prime factor, all other factors are even integers that are not prime.
Therefore, the greatest prime factor of {22}+{20} is 23.

Option A is correct.

Hope it helps.
I am available if you'd like any follow up.
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by Scott@TargetTestPrep » Tue Nov 12, 2019 7:15 pm
BTGmoderatorRO wrote:If {x} is the product of all even integers from 1 to x inclusive, what is the greatest prime factor of {22} + {20}?
A) 23
B) 20
C) 11
D) 5
E) 2
OA is a
What is the correct answer here how do you arrive at it? please help me out.
Thanks
{22} = 22 x 20 x 18 x 16 x ... 4 x 2

{20} = 20 x 18 x 16 x ... 4 x 2

{22} + {20} = (22 x 20 x 18 x 16 x ... 4 x 2) + (20 x 18 x 16 x ... 4 x 2)

From the two terms above, we pull out the common factor of (20 x 18 x 16 x ... 4 x 2), yielding:

{22} + {20} = 20 x 18 x 16 x ... 4 x 2 x (22 + 1)

{22} + {20} = 20 x 18 x 16 x ... 4 x 2 x 23

We see that the greatest prime factor is 23.

Answer: A

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by swerve » Thu Nov 14, 2019 6:58 am
BTGmoderatorRO wrote:If {x} is the product of all even integers from 1 to x inclusive, what is the greatest prime factor of {22} + {20}?
A) 23
B) 20
C) 11
D) 5
E) 2
OA is a
What is the correct answer here how do you arrive at it? please help me out.
Thanks
Now if \(\{x\}\) is the product of all even integers from 1 to \(x\) inclusive, this means

we can take 20 common from \(\{22\} + \{20\}\)

\(20\times 18 \cdots 2 (22 + 1)\)

\(23 \times \) Some expression

23 \(\Rightarrow\) __A__.

Greatest prime factor.
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