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Source: — Data Sufficiency |
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Re: Prep1: s and t are two different numbers on number line.

by parallel_chase » Fri Oct 31, 2008 5:55 am
nandansingh wrote:If s and t are two different numbers on number line, is s+t equal to 0 ?
1. The distance between s and 0 is the same as the distance between t and 0.
2. 0 is between s and t.

OA: a
question stem:
s+t=0, this can only be possible if s and t have the same absolute value but different signs.
therefore, we are just trying to find if lsl = ltl ?

Statement I
ls-0l = lt-0l
lsl = ltl
Sufficient.

Statement II

We dont know if s and t have the same absolute value, we just know that one is negative and one is positive.

Hence A.

Hope this helps.
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Re: Prep1: s and t are two different numbers on number line.

by nandansingh » Fri Oct 31, 2008 6:02 am
parallel_chase wrote:
nandansingh wrote:If s and t are two different numbers on number line, is s+t equal to 0 ?
1. The distance between s and 0 is the same as the distance between t and 0.
2. 0 is between s and t.

OA: a
question stem:
s+t=0, this can only be possible if s and t have the same absolute value but different signs.
therefore, we are just trying to find if lsl = ltl ?

Statement I
ls-0l = lt-0l
lsl = ltl
Sufficient.

Statement II

We dont know if s and t have the same absolute value, we just know that one is negative and one is positive.

Hence A.

Hope this helps.
One doubt...
Statement-2: Zero is between s and t.
Does that not mean that 0 is right in-between and hence the midpoint between s and t. hence s and t have same absolute value but opposite sign. hence s+t=0!
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Re: Prep1: s and t are two different numbers on number line.

by parallel_chase » Fri Oct 31, 2008 6:07 am
nandansingh wrote: One doubt...
Statement-2: Zero is between s and t.
Does that not mean that 0 is right in-between and hence the midpoint between s and t. hence s and t have same absolute value but opposite sign. hence s+t=0!
I think that would be an assumption.

If the statement would have said " 0 is half way between s and t" then probably we would have taken 0 as the mid point.

But in this case,

if s= -3 and t=5

we can still say that 0 is between s and t, but we dont know 0 is how far away from s and t.

Hope this helps.
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by nandansingh » Fri Oct 31, 2008 6:10 am
Thanks a lot parallel_chase!!!
You simply rocked the show!!!
GOD BLESS YOU.
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by bluementor » Sun Nov 02, 2008 9:34 am
parallel_chase,

I believe statement 1 is not sufficient on its own:

If |s| = |t|, this can be satisfied for eg. by (s,t) = (5, -5) and (s,t) = (5, 5). Both will yield different answers to the question stem while still keeping statement 1 true. Therefore, it is insufficient.

Together with the info from statement 2, you can prove that s and t have different signs, hence answer C.

Let me know what you think.

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by krazy800 » Sun Nov 02, 2008 10:08 am
s and t should be different numbers as given in the problem.......
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by bluementor » Mon Nov 03, 2008 12:06 am
krazy800 wrote:s and t should be different numbers as given in the problem.......
you're right!!... :D. I really need to stop doing silly mistakes like this...

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