Kindly help me to solve attached problems
Thanks,
Shobha
Thanks,
Shobha
- Attachments
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- Geometry.doc
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The first one is easy;
30*40 + ((20^2 * pi/2)-(10^2*pi/2)) = 1200 + 150pi = E
The second one;
the hypotenuse of the whole triangle is 5, so use the following equation where 5 is split up into x and 5-x, so,
sqrt(3^2-x^2) = sqrt(4^2 - (5-x)^2)
solve that equation and you get x = 9/5 or 1.8
Then, we use the Pythagoras theorem;
sqrt(3^2 - (9/5)^2) = sqrt(144/25) = 12/5
