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Population

Expert replies
by Juggernaut_86 » Mon Sep 05, 2011 5:59 pm
A certain city with a population of 132000 is to be distributed into 11 voting districts, and no district is to have a population that is more than 10% greater than the population of any other district. What is the minimum population that the least populted district could have?

(A)10700
(B)10800
(C)10900
(D)11000
(E)11100

OA - D

Could anyone please explain a quick way to solve this under 3 minutes?

Thanks!
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Source: — Problem Solving |

by edvhou812 » Mon Sep 05, 2011 6:11 pm
I don't know what to say, really. Three minutes to the biggest battle of our professional lives. You find out life's this game of inches, so is football. Because in either game - life or football - the margin for error is so small. I mean, one half a step too late or too early and you don't quite make it. One half second too slow, too fast and you don't quite catch it. I'll tell you this, in any fight it's the guy whose willing to die whose gonna win that inch. That's football guys, that's all it is. Now, what are you gonna do?
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by Anurag@Gurome » Mon Sep 05, 2011 6:45 pm
Juggernaut_86 wrote:A certain city with a population of 132000 is to be distributed into 11 voting districts, and no district is to have a population that is more than 10% greater than the population of any other district. What is the minimum population that the least populted district could have?

(A)10700
(B)10800
(C)10900
(D)11000
(E)11100

OA - D

Could anyone please explain a quick way to solve this under 3 minutes?

Thanks!
Let the 11 voting districts have populations d1, d2, d3, d4,....d11 respectively.
Let d1 be the least population.
So, d1+d2+d3+...+d11 = 132,000.
Now, according to question d2 <= 1.1*d1, d3 <= 1.1*d1,....d11<=1.1*d1.
Adding all inequality, we get that (d2+d3+d4...d11) <= 10*1.1*d1.
Or (d2+d3+d4...d11) <= 11d1.
Or (d1+d2+...+d11) <= 12d1.
Or 132,000 <= 12d1.
Or d1 => 11,000.
So, the minimum possible population of least populated district is 11,000.

The correct answer is D.
Anurag Mairal, Ph.D., MBA
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by Juggernaut_86 » Mon Sep 05, 2011 8:22 pm
Hi Anurag,

I understand the logic now. Thanks for replying.
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by Anurag@Gurome » Mon Sep 05, 2011 8:24 pm
Juggernaut_86 wrote:Hi Anurag,

I understand the logic now. Thanks for replying.
You are welcome!
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by mehrasa » Mon Sep 05, 2011 9:01 pm
so this means that the population of d1=11000 and the other regions all have the same population =1.1d1
does it make sense? i can,t undrestand
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by saketk » Tue Sep 06, 2011 9:33 am
Juggernaut_86 wrote:A certain city with a population of 132000 is to be distributed into 11 voting districts, and no district is to have a population that is more than 10% greater than the population of any other district. What is the minimum population that the least populted district could have?

(A)10700
(B)10800
(C)10900
(D)11000
(E)11100

OA - D

Could anyone please explain a quick way to solve this under 3 minutes?

Thanks!
Hi - Although you got an excellent reply from Anurag, i'll try to explain what i did.

work with small numbers -- I took 132 only.

132/11 = 12 i.e. if all states have to have the same population, it will be 12

10% of 12 is 1.2
also, 12-1.2 = 10.8
But, if we keep the population of one state = 10.8 then other states will have to share the remaining 1.2 part.. that will clearly violate the condition (Population not more than 10%)
So our answer has to be bigger than 10.8 -- This eliminates option A & B.
Also, if you see the option C, it is very close to option B. So I parked this choice for some time.
Then I jumped to the next choice i.e. 11000.

if i put 11 as the population of 1 state.. other states will have to share the remaining (121 in this case)-- 132-11 = 121.. that mean the population of remaining 10 states will be 12.1 each. And 10% of 11 is 1.1

Hurrah! :) This satisfies the constraint given in the question. CORRECT answer: - D :D

I used timer here and took exactly 2 mins to solve this one.. I think i did OK.
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