BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
Vote for Target Test Prep, Newsweek Readers’ Choice Awards 2026
NEWSWEEK READERS’ CHOICE 2026

BIG NEWS! Target Test Prep has been nominated, and they’d love your vote!

TTP has worked incredibly hard to build the best test prep experience possible, and winning Newsweek’s 2026 Readers’ Choice Award for Best Test Prep would mean a lot to them. If TTP has helped you, they’d be incredibly grateful for your vote. You can vote once each day through September 9.

Vote for TTP
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Pool X and Pool Y

Expert replies
by chipbmk » Mon Dec 07, 2009 11:55 am
If Pool Y currently contains more water than Pool X, and if Pool X is currently filled to 2/7 of its capacity, what percent of the water currently in Pool Y needs to be transferred to Pool X if Pool X and Pool Y are to have equal volumes of water?

(1) If all the water currently in Pool Y were transferred to Pool X, Pool X would be filled to 6/7 of its capacity.

(2) Pool X has a capacity of 14,000 gallons.

OA: A

Please be as detailed as possible, I have already read through the official answer from MGMAT and I am still confused. Pretend you are explaining this to a 5th grader :)

Thanks!
Join the discussion
Source: — Data Sufficiency |

by djkvakin » Mon Dec 07, 2009 3:51 pm
Pool x is filled up to 2/7 of it's capacity. Let's look at condition I:
It tells us that if we add all the water from Y to X, X will get filled up to 6/7 of the capacity. That means that together both pools contain 6/7 of the water to fill pool X. To equalize the amount of water in both pools we need each pool have 3/7 of the water (that is 6/7 divided by 2). Since pool Y contains 4/7 (that we know because 6/7-2/7=4/7). we know that 1/7 of the water from pool Y has to be transfered to pool X. Our answer then will be 1/7*100%.
Condition II tells us nothing about pool Y. Hence, the answer is A.
Join the discussion

by chipbmk » Mon Dec 07, 2009 4:47 pm
AAAHHH much better explanation than the official MGMAT.

Thanks!
Join the discussion

by beatthegmat » Mon Dec 07, 2009 5:22 pm
Nice explanation, djkvakin!
Beat The GMAT | The MBA Social Network
Community Management Team

Research Top GMAT Prep Courses:
https://www.beatthegmat.com/gmat-prep-courses

Research The World's Top MBA Programs:
https://www.beatthegmat.com/mba/school
Join the discussion

by viju9162 » Mon Dec 07, 2009 11:13 pm
very nice explanation djkvakin.

Thank you.

Regards,
Viju
"Native of" is used for a individual while "Native to" is used for a large group
Join the discussion

by asafe » Tue Dec 08, 2009 1:26 am
djkvakin wrote:Pool x is filled up to 2/7 of it's capacity. Let's look at condition I:
It tells us that if we add all the water from Y to X, X will get filled up to 6/7 of the capacity. That means that together both pools contain 6/7 of the water to fill pool X. To equalize the amount of water in both pools we need each pool have 3/7 of the water (that is 6/7 divided by 2). Since pool Y contains 4/7 (that we know because 6/7-2/7=4/7). we know that 1/7 of the water from pool Y has to be transfered to pool X. Our answer then will be 1/7*100%.
Condition II tells us nothing about pool Y. Hence, the answer is A.

I agree with answer A, but shouldn't the amount to be transfered be 1/4 of pool Y ?
Y contains 4/7 of X => tranfering 1/7 of X means a 1/4 of Y.
Join the discussion

by djkvakin » Tue Dec 08, 2009 8:51 am
asafe wrote:
djkvakin wrote:Pool x is filled up to 2/7 of it's capacity. Let's look at condition I:
It tells us that if we add all the water from Y to X, X will get filled up to 6/7 of the capacity. That means that together both pools contain 6/7 of the water to fill pool X. To equalize the amount of water in both pools we need each pool have 3/7 of the water (that is 6/7 divided by 2). Since pool Y contains 4/7 (that we know because 6/7-2/7=4/7). we know that 1/7 of the water from pool Y has to be transfered to pool X. Our answer then will be 1/7*100%.
Condition II tells us nothing about pool Y. Hence, the answer is A.

I agree with answer A, but shouldn't the amount to be transfered be 1/4 of pool Y ?
Y contains 4/7 of X => tranfering 1/7 of X means a 1/4 of Y.
I think you are right. I have been thinking about that. very good.
Join the discussion

by bhumika.k.shah » Tue Mar 30, 2010 10:30 am
Any other approaches?
Join the discussion

by kstv » Tue Mar 30, 2010 8:14 pm
Another approach is to make some strategic assumptions.
Volume of Pool X = Volume of Pool Y = 7 litres/gallons or 7000 litres/gallons makes no diff.
Volume of water in X = 2 ltrs or 2000 ltrs based on full capacity assumed.
(1) water of Pool Y emptied into Pool X
Pool X is 6/7 full so it had 6 ltrs
Assuming capacity of 7 ltrs is fine cos after the water of Pool Y is emptied the denominator of the fraction is still 7. #
Easy to see that 4 ltrs have been added from Pool Y
So pool y was 4/7 full.
Adding one litre from Y to X would be enough fro both to be 3/7 full.
Sufficient
(2) pool X has a capacity of 14,000 gallons. djkvakin says that nothing is said about Pool Y but we know capacity of Pool Y = Pool X. Importantly , it does not say how much water is there in Pool Y. Hence insufficient

# if the question said that after water from Pool y is emptied in Pool x , Pool X is 9/13 full then will making assumption work ?
Join the discussion

by Fiver » Wed Mar 31, 2010 5:20 am
chipbmk wrote:If Pool Y currently contains more water than Pool X, and if Pool X is currently filled to 2/7 of its capacity, what percent of the water currently in Pool Y needs to be transferred to Pool X if Pool X and Pool Y are to have equal volumes of water?

(1) If all the water currently in Pool Y were transferred to Pool X, Pool X would be filled to 6/7 of its capacity.

(2) Pool X has a capacity of 14,000 gallons.

OA: A

Please be as detailed as possible, I have already read through the official answer from MGMAT and I am still confused. Pretend you are explaining this to a 5th grader :)

Thanks!
Assume total capacity of pool x =x and that of pool y =y

Current capacity of pool x = 2x/7 and that of y=a*y ('a' because we do not know what fraction of y is currently filled)

The question is
If ay - n = 2x/7 + n, then n/ay = ?

(1) If all the water currently in Pool Y were transferred to Pool X, Pool X would be filled to 6/7 of its capacity.

This means: ay + 2x/7 = 6x/7
Hence ay = 4x/7
Now 4x/7 - n = 2x/7 + n
Therefore n = x/7
and n/ay = x/7 * 7/4x = 25%
Join the discussion