BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Pls help on GMAT Prep Q

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Data Sufficiency |
Master | Next Rank: 500 Posts
Posts: 229
Joined: Thu Nov 08, 2007 3:47 pm
Thanked: 14 times
GMAT Score:750

Forgot to add the attachement

by LSB » Tue Aug 26, 2008 11:34 am
Forgot to add the attachement
Attachments
capture1.jpg
Forgot to add the attachement
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 12
Joined: Thu Aug 21, 2008 9:46 am
Location: India
Thanked: 1 times

by gautamberry » Tue Aug 26, 2008 1:02 pm
here it goes..

Angle R=90-T
Angle T=90-R

In triangle RQS

Since triangle RQS is isosceles angle Q= angle S (say A)
R+Q+S=180
90-T+2A=180
A=(90+T)/2


In triangle TSU

Since triangle TSU is isosceles angle U= angle S (say B)
T+S+U=180
90-R+2B=180
B=(90+R)/2


Now for line RST

angle RSQ + angle QSU + angle TSU = 180

A+X+B=180

(90+T)/2 + X + (90+R)/2 = 180

(90+T+2X+90+R)/2 = 180

(180+90+2X)/2 = 180 (Since angle R + angle T + 90 = 180 .....the triangle RPT)

(270+2X)/2 = 180

135+X = 180

X = 45

Hence the answer is C


Hope you got it!!!!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 24
Joined: Thu Jun 26, 2008 7:21 am

by arvindm07 » Tue Aug 26, 2008 1:37 pm
gautamberry wrote:here it goes..

Angle R=90-T
Angle T=90-R

In triangle RQS

Since triangle RQS is isosceles angle Q= angle S (say A)
R+Q+S=180
90-T+2A=180
A=(90+T)/2


In triangle TSU

Since triangle TSU is isosceles angle U= angle S (say B)
T+S+U=180
90-R+2B=180
B=(90+R)/2


Now for line RST

angle RSQ + angle QSU + angle TSU = 180

A+X+B=180

(90+T)/2 + X + (90+R)/2 = 180

(90+T+2X+90+R)/2 = 180

(180+90+2X)/2 = 180 (Since angle R + angle T + 90 = 180 .....the triangle RPT)

(270+2X)/2 = 180

135+X = 180

X = 45
Hence the answer is C


Hope you got it!!!!
or

B+x = A + R R=90-T
=> B + x = A + 90-T
and A + x = B + T

adding both we have
A+B+2x = A+B+90
therefore, 2x=90 or x=45
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 229
Joined: Thu Nov 08, 2007 3:47 pm
Thanked: 14 times
GMAT Score:750

by LSB » Tue Aug 26, 2008 1:47 pm
arvindm07 wrote:
gautamberry wrote:here it goes..

Angle R=90-T
Angle T=90-R

In triangle RQS

Since triangle RQS is isosceles angle Q= angle S (say A)
R+Q+S=180
90-T+2A=180
A=(90+T)/2


In triangle TSU

Since triangle TSU is isosceles angle U= angle S (say B)
T+S+U=180
90-R+2B=180
B=(90+R)/2


Now for line RST

angle RSQ + angle QSU + angle TSU = 180

A+X+B=180

(90+T)/2 + X + (90+R)/2 = 180

(90+T+2X+90+R)/2 = 180

(180+90+2X)/2 = 180 (Since angle R + angle T + 90 = 180 .....the triangle RPT)

(270+2X)/2 = 180

135+X = 180

X = 45
Hence the answer is C


Hope you got it!!!!
or

B+x = A + R R=90-T
=> B + x = A + 90-T
and A + x = B + T

adding both we have
A+B+2x = A+B+90
therefore, 2x=90 or x=45
What's the rule behind
B+x = A + R
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 24
Joined: Thu Jun 26, 2008 7:21 am

by arvindm07 » Tue Aug 26, 2008 4:01 pm
LSB wrote:
arvindm07 wrote:
gautamberry wrote:here it goes..

Angle R=90-T
Angle T=90-R

In triangle RQS

Since triangle RQS is isosceles angle Q= angle S (say A)
R+Q+S=180
90-T+2A=180
A=(90+T)/2


In triangle TSU

Since triangle TSU is isosceles angle U= angle S (say B)
T+S+U=180
90-R+2B=180
B=(90+R)/2


Now for line RST

angle RSQ + angle QSU + angle TSU = 180

A+X+B=180

(90+T)/2 + X + (90+R)/2 = 180

(90+T+2X+90+R)/2 = 180

(180+90+2X)/2 = 180 (Since angle R + angle T + 90 = 180 .....the triangle RPT)

(270+2X)/2 = 180

135+X = 180

X = 45
Hence the answer is C


Hope you got it!!!!
or

B+x = A + R R=90-T
=> B + x = A + 90-T
and A + x = B + T

adding both we have
A+B+2x = A+B+90
therefore, 2x=90 or x=45
What's the rule behind
B+x = A + R
Exterior angle of a triangle is equal to the sum of the opposite interior angles.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 132
Joined: Fri Sep 05, 2008 10:19 pm
Location: Bangladesh
Thanked: 1 times

by rabab » Wed Sep 10, 2008 10:14 am
1 says- QR = RS
hence angle RQS = angle RSQ, let angle RQS = angle RSQ = y.

in triangle RQS,
y + y + angle QRS = 180 degree
-> angle QRS = 180 degree - 2y ---- eqn i

now, from 2 we get,
ST = TU
-> angle SUT = angle STU. let angle SUT = angle STU = z

in triangle STU
z + z + angle STU = 180 degree
-> angle STU = 180 - 2z --- eqn ii

now, in triangle RPT,
angle RTP + angle STU + angle PRS = 180 degree
-> 90 degree + (180 - 2z) + (180 degree - 2y) = 180 degree ( solved from eqn i & ii)

-> y+ z = 136 degree -- eqn iii

now,
angle x + angle y + angle z = 180 degree
-> angle x = 180 - 135 (solved from eqn iii)
therefore angle x = 45 degree.


hope it helps
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 353
Joined: Sat Jan 20, 2007 1:29 am
Location: Italy
Thanked: 7 times
GMAT Score:720

by mjjking » Fri Apr 03, 2009 12:26 pm
While the angle is 90-T and not 180-90-T??!
Beat The GMAT - 1st priority
Enter a top MBA program - 2nd priority
Loving my wife: MOST IMPORTANT OF ALL!

REAL THING 1 (AUG 2007): 680 (Q43, V40)
REAL THING 2 (APR 2009): 720 (Q47, V41)
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1