Inequalities

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Inequalities

by vinni.k » Thu Dec 15, 2011 12:22 pm
Is x^3 > X^2 ?

(1) x > 0
(2) x^2 > x

Answer is C

Why not answer is E ?

Thanks & Regards
Vinni
Source: — Data Sufficiency |

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by GmatMathPro » Thu Dec 15, 2011 12:40 pm
Is x^3>x^2?

Rewriting:

Is x^3-x^2>0?

Is x^2(x-1)>0?

This will be true if x>1 and false if x<1.

Statement 1: x>0. From the above analysis, the question will be true if x>1, such as 2, but false if 0<x<=1, such as 1/2, both of which are possible if x>0. INSUFFICIENT.

Statement 2: x^2>x, or x^2-x>0 or x(x-1)>0. This is means that either x>1 or x<0. If x>1, x^3>x^2 is true. If x<0, it is false. INSUFFICIENT.

Statements 1&2: If we know that x>0 (from statement 1), then the only way statement 2 could be true is if x>1. Thus, x is definitely greater than 1. We already demonstrated that x^3>x^2 is always true when x>1. SUFFICIENT.
vinni.k wrote:Is x^3 > X^2 ?

(1) x > 0
(2) x^2 > x

Answer is C

Why not answer is E ?

Thanks & Regards
Vinni
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by neelgandham » Thu Dec 15, 2011 12:48 pm
Is x^3 > x^2 ?

Case 1: For all x,where x<0, x^3<x^2.
If x=-1, x^3 = -1, x^2 = 1, x^3 < x^2
If x=0, x^3 = 0, x^2 = 0, x^3 = x^2

Case 2:For all x, where 0<x<1, x^3<x^2
If x=1/2, x^3 = 1/8, x^2 = 1/4, x^3 < x^2
If x=1, x^3 = 1, x^2 = 1, x^3 = x^2

Case 3: For all x, where x>1, x^3>x^2
If x =2, x^3 = 8, x^2 = 4, x^3 > x^2

So the question can be rephrased to :Is x > 1?
(1) x > 0
Insufficient, as the value of x can be less than 1(e.g. 1/2 > 0) or greater than 1(e.g. 2 > 0)
(2) x^2 > x
Insufficient, as the conditions x<0 and x>1 satisfy the equation above.

From statement 1 and 2
Intersection of x>0 AND (x<0 and x>1) is x>1 Hence sufficient

Answer C. We can explain you better if you tell us why you think you cannot answer the question using both the statements!
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by vinni.k » Fri Dec 16, 2011 1:05 am
Pete and neelgandham, thank you very much for clearing my doubt.

Regards
Vinni