BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

GMAT Prep / Combinatorics

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Problem Solving |
Senior | Next Rank: 100 Posts
Posts: 95
Joined: Fri Sep 28, 2007 10:16 am
Thanked: 6 times
GMAT Score:710

by muzali » Tue Dec 02, 2008 5:22 pm
Atleast one French member = (1F out of total 3)+(2F out of total 3)+(3F out of total 3)

=(4C1*6C2) + (4C2*6C1) + (4C3)
=4*15 + 6*6 + 4
=60+36+4
=100
Top
Master | Next Rank: 500 Posts
Posts: 207
Joined: Sun Mar 11, 2007 6:16 pm
Location: Mumbai
Thanked: 11 times

by jimmiejaz » Wed Dec 03, 2008 7:21 am
You can also solve this question as....
We have to find no of ways containing atleast one french.
We can find no of ways in which no french member is selected and subtract it from total.
10C3 - 6C3
= 100
What if i have not yet beat the beast, I know i will beat it!!!!!!!!
Top
Senior | Next Rank: 100 Posts
Posts: 65
Joined: Thu Nov 13, 2008 8:03 am
Location: Paris, France
Thanked: 2 times
GMAT Score:730

by Carloblacksun » Wed Dec 03, 2008 7:55 am
I had the same approach as Jimmy!!
Good one!
Top
Post new topic Post Reply
• Page 1 of 1