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Playing mixed doubles

Expert replies

by g_beatthegmat » Tue Jun 17, 2008 5:28 pm
thanks much Motherjane and Ian!
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Re: Generalized soln

by chidcguy » Tue Jun 17, 2008 7:14 pm
shankyrams wrote:I think the answer is 105.
If there are X*Y people who are put in X groups containing Y people each the this can be done in [ (X*Y) ! / ((X!)*(Y^X)) ] ways.
This is a great way of doing it if we can

(1) identify the problem and remember the formula in the heat of the test

(2) be careful in not confusing some other problem as this problem and end up with the wrong answer.
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by anayak » Tue Jun 17, 2008 7:18 pm
Stuart, Great Explanaiton
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