{(x^2+6x-7)}/{|x+4|} < 0
A) -7<x<-5 and -4<x<1
B) -7<x<-5 and -4<x<0
C) -7<x<-4 and -4<x<1
D) -7<x<-6 and -4<x<1
A) -7<x<-5 and -4<x<1
B) -7<x<-5 and -4<x<0
C) -7<x<-4 and -4<x<1
D) -7<x<-6 and -4<x<1
Hi shibsriz,
While this question can be solved mathematically, there's a great way to eliminate answers by TESTing Values.
First, notice how the answer choices "overlap" a bit; this "overlap" gives us an idea of Values that we should TEST.
We need values of X that make the given calculation less than 0. You should notice that the denominator is built around an absolute value, so the denominator will always be POSITIVE. This means the numerator is what we need to make NEGATIVE.
X^2 +6X - 7 < 0
As far as what X COULD be....
X = 0 is a possibility, since 0^2 + 6(0) - 7 is less than 0. Eliminate answer B
X = -5 is a possibility, since (-5)^2 +6(-5) - 7 is less than 0. Eliminate answer A and D
Final Answer: C
GMAT assassins aren't born, they're made,
Rich
