There are 5 cars to be displayed in 5 parking spaces with all the cars facing the same direction.
Of the 5 cars, 3 are red, 1 is blue, and 1 is yellow. If the cars are identical except for color, how
many different display arrangements of the 5 cars are possible?
A. 20
B. 25
C. 40
D. 60
E. 125
Is C not the correct answer? I got 20 as the number of arrangements if the cars are displayed in one direction. But if we reverse the direction of all cars, the total arrangements will be 20*2=40. Did I assume beyond what is stated in the problem?
OA – A
Of the 5 cars, 3 are red, 1 is blue, and 1 is yellow. If the cars are identical except for color, how
many different display arrangements of the 5 cars are possible?
A. 20
B. 25
C. 40
D. 60
E. 125
Is C not the correct answer? I got 20 as the number of arrangements if the cars are displayed in one direction. But if we reverse the direction of all cars, the total arrangements will be 20*2=40. Did I assume beyond what is stated in the problem?
OA – A
Last edited by crackgmat007 on Sun May 10, 2009 9:31 pm, edited 1 time in total.
