You have 6 two dollar coins, 6 one dollar coins and 3 fifty cent coins. How many different sums can you pay with these coins?
A) 15
B) 50
C) 60
D) 38
E) 100
OA: 38
Permutation
This topic has expert replies
-
- Junior | Next Rank: 30 Posts
- Posts: 14
- Joined: Wed Apr 22, 2009 10:00 am
- Thanked: 1 times
-
- Senior | Next Rank: 100 Posts
- Posts: 60
- Joined: Thu Feb 26, 2009 12:50 pm
- Location: Chicago
- Thanked: 3 times
This doesn't seem like a very likely question but I would guess D. It doesn't specify if we must use atleast one of each coin or not, so the combinations become complicated but by writing a bunch out I could see we can get any integer value 1-19 inclusive = 20 and any 50cent increment from .50-19.50 = 20 so the total would be 40.