BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
Vote for Target Test Prep, Newsweek Readers’ Choice Awards 2026
NEWSWEEK READERS’ CHOICE 2026

BIG NEWS! Target Test Prep has been nominated, and they’d love your vote!

TTP has worked incredibly hard to build the best test prep experience possible, and winning Newsweek’s 2026 Readers’ Choice Award for Best Test Prep would mean a lot to them. If TTP has helped you, they’d be incredibly grateful for your vote. You can vote once each day through September 9.

Vote for TTP
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Triangles

Expert replies
by shankar.ashwin » Sat Jan 07, 2012 9:05 pm
A 25 ft long ladder is placed against the wall with its base 7 ft from the wall. The base of the ladder is drawn out so that the top comes down by half the distance that the base is drawn out. This distance is in the range:

A (5,8)
B (9,10)
C (2,7)
D (3,7)
E None of the above

[spoiler]Don't have a OA and don't exactly get what the questions asks.[/spoiler]

COuld someone help..Tough one I assume
Join the discussion
Source: — Problem Solving |

by pemdas » Sun Jan 08, 2012 12:26 am
Here we need to find within which range of values the distance of ladder jacked out (not 25 ft, but jacked out distance) is placed. The jacked out ladder's top has height of half the distance this ladder is jacked out.

The geometric figure will be a right triangle with the sides: base 7, height x/2, ladder's length x (jacked out). We should solve for x, and there's proportion such as 1:sqrt(3):2 (30-60-90 degrees). Hence, 7=sqrt(3)*(x/2) and 49=(3x^2)/4, 3x^2=196, x^2=~65, x is closer to 8 but is slightly greater, some 8.1.

let's see which answer choice contains 8.1

A (5,8) no
B (9,10) no
C (2,7) no
D (3,7) no
E None of the above :) Yes

e

[spoiler]on the second read after solving, i guess wording here is abra-cadabra (confusing), mainly relied on common sense about the object in q.
[/spoiler]
shankar.ashwin wrote:A 25 ft long ladder is placed against the wall with its base 7 ft from the wall. The base of the ladder is drawn out so that the top comes down by half the distance that the base is drawn out. This distance is in the range:

A (5,8)
B (9,10)
C (2,7)
D (3,7)
E None of the above

[spoiler]Don't have a OA and don't exactly get what the questions asks.[/spoiler]

COuld someone help..Tough one I assume
Success doesn't come overnight!
Join the discussion

by neelgandham » Mon Jan 09, 2012 5:57 am
I might be wrong, but he is what I think.

Initial position : Right angled triangle ABC
7,24,25 is the pythagorean triple. So distance of the topmost point of the ladder to the ground is 24 ft.

Final position: Right angled triangle A'B'C
The base of the ladder is drawn out so that the top comes down by half the distance that the base is drawn out. So if the ladder is drawn out by x ft, then the top comes down BY 0.5x. Pythagorean theorem comes into picture now.

(24-0.5x)^2 + (7+x)^2 = 25^2
24^2 + 0.25x^2 - 24x + 49 + x^2 + 14x = 25^2
0.25x^2 - 24x x^2 + 14x
1.25x^2 - 10x = 0
1.25x(x -8) = 0
x = 8

Should be A if 8 is included in the set or E if it isn't.
Attachments
Beatthegmat_31.JPG
Anil Gandham
Welcome to BEATtheGMAT | Photography | Getting Started | BTG Community rules | MBA Watch
Check out GMAT Prep Now's online course at https://www.gmatprepnow.com/
Join the discussion

by ArunangsuSahu » Mon Jan 09, 2012 1:28 pm
This is a problem of Rearrangement of Hypotenuse

Eqn 1: 25^2=24^2+7^2

Eqn 2: 25^2=(24-x)^2+(7+2x)^2

Find out 2x

2x = 8

This distance is in the range:

(A) should be the answer if the range here means inclusive else (E)
Join the discussion