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permutation problem I think

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by eclaym2003 » Wed May 27, 2009 10:27 am
A certain company employs 6 senior officers and 4 junior officers. If a committee is to be created that is made up of 3 senior officers and 1 junior officer, how many different committees are possible?

Answer choices:

8
24
58
80
210
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by p2pg » Wed May 27, 2009 10:33 am
IMO D 6C3*4
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by eclaym2003 » Wed May 27, 2009 10:43 am
thanks but i'm not sure what that means.
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by ket » Wed May 27, 2009 11:01 am
In order to find out the answer you have to

1. find out how many different groups of 3 senior officers can be selected from 6 persons this is denoted as 6C3 the formula is 6!/ (3!*3!) = 20
{nCk=n!/(k!(n-k)!}


2. find out how many different kind of junior judges can be selected from 4 judges - that is obvious to be 4

3. multiply the answers in step 1 and step 2 in order to arrive at how many different committees are possible i.e. 20*4=80.
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