A certain company employs 6 senior officers and 4 junior officers. If a committee is to be created that is made up of 3 senior officers and 1 junior officer, how many different committees are possible?
Answer choices:
8
24
58
80
210
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permutation problem I think
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eclaym2003
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eclaym2003
- Junior | Next Rank: 30 Posts
- Posts: 26
- Joined: Sat Feb 02, 2008 11:08 pm
In order to find out the answer you have to
1. find out how many different groups of 3 senior officers can be selected from 6 persons this is denoted as 6C3 the formula is 6!/ (3!*3!) = 20
{nCk=n!/(k!(n-k)!}
2. find out how many different kind of junior judges can be selected from 4 judges - that is obvious to be 4
3. multiply the answers in step 1 and step 2 in order to arrive at how many different committees are possible i.e. 20*4=80.
1. find out how many different groups of 3 senior officers can be selected from 6 persons this is denoted as 6C3 the formula is 6!/ (3!*3!) = 20
{nCk=n!/(k!(n-k)!}
2. find out how many different kind of junior judges can be selected from 4 judges - that is obvious to be 4
3. multiply the answers in step 1 and step 2 in order to arrive at how many different committees are possible i.e. 20*4=80.
