Permutation and Combination Problem

ganeshrkamath's solution is perfect, and the answer is, indeed, 12C9
However, it's unlikely that the answer choices would be in the form xCy (since there are different ways to denote combinations). For this particular question, we'd probably have to evaluate 12C9. So, let's do that (quickly!!).

If anyone is interested, we have a free video on calculating combinations in your head: https://www.gmatprepnow.com/module/gmat-counting?id=789

When calculating combinations (in our head), it's useful to know the following rule: nCr = nC(n-r). In other words, "n choose r" is equal to "n choose n-r"
So, for example: 10C7 = 10C3
8C7 = 8C1
20C18 = 20C2

This rule is useful because it's much easier to calculate combinations when the second value is smaller.

So, here 12C9 = 12C3
= (12)(11)(10)/(3)(2)(1)
= (2)(11)(10)
= 220

Cheers,
Brent