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Perimeter of right trinangle with longer leg 2s ?

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by stop@800 » Sun Nov 09, 2008 4:11 am
I am with C

sides will be
2S/sqrt(3) 2s 4S/sqrt(3)

as sides has to be in ratio
1 sqrt(3) 2
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by cartera » Sun Nov 09, 2008 6:09 am
I dont understand, the a 30-60-90 triangle should be:

s+2s+s√3 then it should be 3s+s√3 = s(3+√3)
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by jimmiejaz » Sun Nov 09, 2008 6:15 am
cartera wrote:I dont understand, the a 30-60-90 triangle should be:

s+2s+s√3 then it should be 3s+s√3 = s(3+√3)
the answer is C.
i think as the question says the longer side and not the longest, the trick is there.
So as figured out, the sides are in ratio 1:√3:2
so C matches the perimeter.
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