MI3 wrote:Hello,

Can someone assist on the below problem:

In the month of June, a street vendor sold 10% more hot dogs than he sold in the month of May. How many total hot dogs did the vendor sell in May and June?
(1) The vendor sold 27 more hot dogs in June than in May.
(2) In July, the vendor sold 20% more hot dogs than he sold in May.

I chose answer [/spoiler]E , but not very sure.. Please advise, thanks.

Let the vendor sold X no. of hot dogs in May.
No. of hot dogs he sold in June = X + 10% of X = X + 0.1X = 1.1X

(1) No. of hot dogs he sold in June = X + 27 = 1.1X implies 0.1X = 27 or X = 270.
So, no. of hot dogs sold in May and June together = 270 + (270 + 27) = 567
Hence, (1) is SUFFICIENT.

Note: There is no need to do all the calculations in actual test, just determine whether statement is sufficient or not. I have explained here in detail for your clarification.

(2) No. of hot dogs sold in July = X + 20% 0f X, but clearly this info this NOT sufficient to answer the question.
Hence, (2) is NOT sufficient.

The correct answer is A.