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assitant problem

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by pradeepkaushal9518 » Wed May 19, 2010 5:14 am
issen is trying to select an assistant from a pool A application,if 1/5 of them really want to be actors,and of those 2/3 really want to be directors, then in terms of A, how many of the applicants dont want to be both actors and directors?

A. 2A/15
b.A/5
C.A/3
D.7A/8
E.13A/15
Last edited by pradeepkaushal9518 on Wed May 19, 2010 6:04 am, edited 1 time in total.
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by liferocks » Wed May 19, 2010 5:18 am
it should be A{1-(1/5+2/3)}=2A/15 if we assume no one wants to be both actor as well as director
Not sure whether we can assume this.If we can Ans is option A
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by pradeepkaushal9518 » Wed May 19, 2010 5:57 am
no A is not correct i will give oa after sum more discussion
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by asamaverick » Wed May 19, 2010 6:22 am
pradeepkaushal9518 wrote:issen is trying to select an assistant from a pool A application,if 1/5 of them really want to be actors,and of those 2/3 really want to be directors, then in terms of A, how many of the applicants dont want to be both actors and directors?

A. 2A/15
b.A/5
C.A/3
D.7A/8
E.13A/15

A/5 want to be actors. Of these 2/3 want to be directors = A/5 * 2/3 = 2A/15.
The way I interpret it, 2A/15 want to be both actor and director. So the number of people who do not want to be both actor & director = A - 2A/15 = 13A/15.
So IMO it's E.
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by dkumar.83 » Wed May 19, 2010 7:07 am
Total = a.
Actors = a/5.
wanna be directors = (a/5) * 2/3 = a2/15.

Don't wanna be actors n directors = a- a/5 - a2/15 = a13/15.
So correct answer is [spoiler]E[spoiler][/spoiler]
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by Ashish8 » Wed May 19, 2010 8:47 am
I agree with asamavrick.

Here are my steps:

first found the LCM of 3 and 5 = 15 = A

(1/5)*15 = 3 = # who want to be actors

(2/3)*3 = 2 want to be be both actors and directors

Number of applicants who don't want to be both = 15 - 2 = 13

plug 15 for A you get E
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by pradeepkaushal9518 » Wed May 19, 2010 10:32 am
yes frns the oa is E
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