Pen distribution

1001 pens and 910 pencils.


910 is less than 1001 so the only maximum way we can distribute equal number of pens and pencils is by giving out

910 pens and 910 pencils


We can not give out 911 pencils --> there are only 910

I figured it out.
You have interpreted the question wrong. It does not require that each student gets one pen or pencil. They can have as many as they want provided all have equal. It also requires that all pens and pencils get handed out so the maximum number of students turns out

As the HCF of 1001 and 910

which in this case is 91.

Thanks

eaakbari wrote:I figured it out.
You have interpreted the question wrong. It does not require that each student gets one pen or pencil. They can have as many as they want provided all have equal. It also requires that all pens and pencils get handed out so the maximum number of students turns out

As the HCF of 1001 and 910

which in this case is 91.

Thanks

prime factors of 1001 = 7 X 13X 11
prime factors of 910 = 7X13X10

take HCF of the both:
--> 7X13=91

91 students

oops .... you are right ...i tend to make silly mistakes on easy questions ....ugh