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by isanju » Tue Apr 12, 2011 9:23 am
So, solving normally or by taking squares of the both sides of equation, the correct answer is C
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by vzzai » Wed Apr 13, 2011 4:40 am
My apologies for the ignorance...

Why can't we rewrite this equation
|x-2| + |x-3| < 0 as |x-2| < -|x-3|
and square both sides?
Thank you,
Vj
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