BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

password codes

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Senior | Next Rank: 100 Posts
Posts: 48
Joined: Wed Aug 27, 2008 9:58 am
by nh8404052006 » Sun Dec 28, 2008 6:44 pm
A software program is designed to generate password codes using alphabet from A to J, how many 4-alphabet password codes can the program generate? (please note: the alphabets are not allowed to repeat itself.)
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Senior | Next Rank: 100 Posts
Posts: 62
Joined: Fri Dec 21, 2007 2:58 pm
Location: Fremont , California
Thanked: 3 times

password codes

by kishore » Sun Dec 28, 2008 7:50 pm
A software program is designed to generate password codes using alphabet from A to J, how many 4-alphabet password codes can the program generate? (please note: the alphabets are not allowed to repeat itself.)?


Answer: A to J there are 10 aplhabets.

Each password is 4 digits length.

Every time you create a password you should pick 4 different letters so that you avoid repetition.

10C4 = 10!/6! * 4! = 210

210 is the correct answer

May I know the IMO?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 37
Joined: Wed Sep 17, 2008 8:17 pm
Location: India
Thanked: 4 times

Re: password codes

by Sachindh » Sun Dec 28, 2008 7:56 pm
nh8404052006 wrote:A software program is designed to generate password codes using alphabet from A to J, how many 4-alphabet password codes can the program generate? (please note: the alphabets are not allowed to repeat itself.)
I think answer would be 10C4 * 4! = 5040.

What is OA?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 48
Joined: Wed Aug 27, 2008 9:58 am

by nh8404052006 » Sun Dec 28, 2008 8:02 pm
OA : [spoiler]10P4 /10^4[/spoiler]
I am not sure the OA is correct or not.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 37
Joined: Wed Sep 17, 2008 8:17 pm
Location: India
Thanked: 4 times

by Sachindh » Sun Dec 28, 2008 8:12 pm
nh8404052006 wrote:OA : [spoiler]10P4 /10^4[/spoiler]
well! If I follow this answer then it can be break down to (9*8*7)/10*10*10 = 0.504.

Isn't there something wrong with the answer stated above by you?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 62
Joined: Fri Dec 21, 2007 2:58 pm
Location: Fremont , California
Thanked: 3 times

by kishore » Sun Dec 28, 2008 8:35 pm
I think answer would be 10C4 * 4! = 5040.???


Can you explain how did u come to this conclusion?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 37
Joined: Wed Sep 17, 2008 8:17 pm
Location: India
Thanked: 4 times

by Sachindh » Sun Dec 28, 2008 8:38 pm
kishore wrote:I think answer would be 10C4 * 4! = 5040.???


Can you explain how did u come to this conclusion?
Selecting 4 alphabets from 10 alphabets = 10C4.
Arranging selected 4 alphabets to created different passcodes = 4!
Total no of ways = 10C4 * 4!

Let me know if there is some thing wrong in the approach.
Thanks
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 621
Joined: Wed Apr 09, 2008 7:13 pmFollowed by: 4 members
Thanked: 33 times

by vittalgmat » Sun Dec 28, 2008 11:43 pm
This is a permutation problem.
I am so happy to see so many ways that this problem can be solved.
I solved it analytically.

There are 10 alphabets and 4 positions.
mark them as
1----2----3----4

1st position can be filled by any 10 alphabets. So 10 ways
2nd position can be filled by any 9 alphabets. So 9 ways
3d " " "" 8 alphabets . So 8 ways
4th position needs 7 ways.

So total ways is a product of all these = 5040 ways.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 2467
Joined: Thu Aug 28, 2008 6:14 pmFollowed by: 11 members
Thanked: 331 times

by cramya » Mon Dec 29, 2008 12:08 am
Agree 100% with some posters on 5040

10*9*8*7
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1