If both ABDC and CDFE are parallelograms, what is q + r?
angle /_ACD=r
angle /_ECD=p
angle /_FDC=q
1) r=70
2 p=110
OA=D
angle /_ACD=r
angle /_ECD=p
angle /_FDC=q
1) r=70
2 p=110
OA=D
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IMO the dig can not look like the way you have shown . For it to be true the <r has to be 90 deg........ankit.k.shrivastava wrote:sorry for posting it in the Ps section. Mods please move it to the DS section.
The diagram may also look like this?
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