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Source: Beat The GMAT — Problem Solving |
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parallel_chase
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sqrt(288xk)ddm wrote:attachment
288 = 2*12*12 = 2^5 3^2
x is divisible by 6
least value of x = 6 = 2*3
288x = 2^6*3^3
sqrt(2^6*3^3*k) = 2^3*3 sqrt(3*k) = 24sqrt(3*k)
the question asks what CANNOT be the value of sqrt(288xk)
eliminate A, C, D because every option does have k in the sqrt with one 3.
Option A can and cannot be the value of sqrt(288xk) because we dont know anything about k.
Option E can also be the value of sqrt(288xk), if x=12
Therefore B is answer. Sorry for the typo.
Let me know if you have any doubts.
Last edited by parallel_chase on Fri Aug 29, 2008 4:11 pm, edited 1 time in total.
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parallel_chase
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