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Expert replies
by harsh.champ » Mon Feb 08, 2010 5:08 am
Out of two -thirds of the total number of basket-ball matches, a team has won 17 matches and lost 3 of them. What is the maximum number of matches that the team can lose and still win three-fourths of the total number of matches, if it is true that no match can end in a tie?

(A)4
(B)6
(C)5
(D)3
(E)None of these

The OA is A.
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Source: — Problem Solving |

by shashank.ism » Mon Feb 08, 2010 5:24 am
harsh.champ wrote:Out of two -thirds of the total number of basket-ball matches, a team has won 17 matches and lost 3 of them. What is the maximum number of matches that the team can lose and still win three-fourths of the total number of matches, if it is true that no match can end in a tie?

(A)4
(B)6
(C)5
(D)3
(E)None of these

The OA is A.
2/3T = 17+3 --> T =30
team wins 3/4th of match i.e. 3/4 x20 = 22.5 i.e.23 matches in all.
There are (30 - 20) = 10 matches remaining. So the team has to win (23 - 17) = 6 of these 10
matches, i.e. it can lose no more than (10 - 6) = 4 matches. Hence[spoiler] option (A). [/spoiler][/spoiler]
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