At Betty's Bagels, bagels normally cost x each, but with purchases of each dozen...

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At Betty's Bagels, bagels normally cost x each, but with purchases of each dozen the customer receives a discount of 1.40 dollars. Billy buys 56 bagels and calculates that he spends an average of 90 cents per bagel. What is the value of x?

A. $1.00
B. $1.40
C. $1.60
D. $2.20
E. $2.75

OA A
Source: — Problem Solving |

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AAPL wrote:
Mon Jun 15, 2020 4:55 am
Princeton Review

At Betty's Bagels, bagels normally cost x each, but with purchases of each dozen, the customer receives a discount of 1.40 dollars. Billy buys 56 bagels and calculates that he spends an average of 90 cents per bagel. What is the value of x?

A. $1.00
B. $1.40
C. $1.60
D. $2.20
E. $2.75

OA A
I assume that bagels normally cost x dollars each.

So, for 56 bagels, normal cost would be 56*100x cents

Let's calculate the discount now. In 56 bagels, there are 4 full dozens, so Betty will get 1.40*4 = 560 cents as a discount

Total payment made to the shop = 5,600x – 560 cents

=> 5,600x – 560 = 56*90

=> x = $1

Correct answer: A

Hope this helps!

-Jay
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AAPL wrote:
Mon Jun 15, 2020 4:55 am
Princeton Review

At Betty's Bagels, bagels normally cost x each, but with purchases of each dozen the customer receives a discount of 1.40 dollars. Billy buys 56 bagels and calculates that he spends an average of 90 cents per bagel. What is the value of x?

A. $1.00
B. $1.40
C. $1.60
D. $2.20
E. $2.75

OA A
Solution:

The total amount of money Billy spent on the bagels is 56 * 0.90 = $50.40. Since 56 bagels are 4 dozens of bagels plus 8 more and the 4 dozens of bagels will receive a discount of 4 x 1.40 = $5.60, we can create the equation:

56x - 5.6 = 50.4

56x = 56

x = 1

Answer: A

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