Word Translation: To fill an order schedule, a manufacturer

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II wrote:See attached problem.
Interested in seeing the different approaches in solving this question.

Thanks in advance.
II
Both Statements 1 & 2 alone are insufficient to answer the question and taken together they still don't offer the value for n. Hence, I chose E.
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by mandy12 » Fri May 16, 2008 7:30 am
I think the answer should be B

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by mim3 » Fri May 16, 2008 8:55 am
mandy12 wrote:I think the answer should be B
What does "meet the schedule" mean from statement 2? If it means "complete the order", then I think the answer is C. If it means, get back to the rate in which is needed to complete the order, I think it's E... I think it means "complete the order", so I'd say the answer is C, which makes me hesitant because it seems to be too obvious, but here's my logic: we know from the stem that it's going to take an average rate of 1000 tools/day and we're asked for the total number or days, n, to complete the order. Because we know that they're not going to give us n directly, we need to find the work (w) for the equation: rate x time= work. Looking at the statments:

1. ok, we're given the rate time and work for the first five days: 600 tools/day for 5 days. So, 3000 tools total. Can't do anything with that.

2. We know that to "meet the schedule" which I take to mean "complete the order", the manufacturer had to crank it up to 1,500 tools/day for the last 4 days. So, the last four days, there were 6000 tools produced. I initially thought this info would be sufficient to answer the question. However, there are a number of combinations of different rates over different periods of time that we average with the rate and work for what's given in statement 2 to get to 1000 tools/day. Because of that, there's more than one answer and 2 is insufficient.

1&2 together: If we know what it took to complete the order from statement 2, then we can plug statement 1 in to the average RTW matrix to get the total number of days, n, which is 9.

I'd love to hear other's thoughts on this one. I'm definitely overthinking it.

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by vittalgmat » Sat May 24, 2008 11:45 pm
What is the OA ??

Thanks
-Vittal

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by ksh » Sun May 25, 2008 9:26 am
IMO B

here stem 2 provides us information that due to problem, last 4 days production was 1500*4=6000 units. if the schedule was 1000 units per day, even though 2 days there was no production, the target of 6 days is met by production in last 4 days.

what's tha OA?

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by netigen » Sun May 25, 2008 1:26 pm
Ans should be E as there is no way to figure out n.

It could be that first 5 days there were problem then 10 days it went smooth at 1000 per day and then last 4 days they had to catch up with 1500 per day.

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by kanha81 » Mon Apr 20, 2009 9:27 am
netigen wrote:Ans should be E as there is no way to figure out n.

It could be that first 5 days there were problem then 10 days it went smooth at 1000 per day and then last 4 days they had to catch up with 1500 per day.
1000 tools --> 1 day
(1000 * n) tools --> n days

Stmt-I
Prod. Problems:
600 tools --> 1 day
(600 * 5) = 3000 tools <-- first 5 days

what about (n-5) days? No information given on that.

Insuff

Stmt-II
Prod Problems:
1500 tools --> 1 day
(1500 * 4) = 6000 tools <-- last 4 days

what about (n-4) days?
Insuff

Stmt-I & Stmt-II:
First 5 days --> 3000 tools
Last 4 days --> 6000 tools
n days ---> (1000 * n) tools.

No way of determining the total number of days.
Insuff

OA [spoiler][E][/spoiler]
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by ketkoag » Wed Apr 22, 2009 2:10 am
yeah E for me as well as there is no way to find out the total days from the given info.