lets think about range of x
0<x<1 and x>1
if x>1 then if x>y x^3>1
but if x<1 then even if x>y it may happen that x^3 < y
stmt 1:
x^1/2 > y
if X>1 then X^3 > 1 but if X<1 even if x^1/2 >y it does not imply x^3 >y INSUF
stmt 2 INSUFF by logic given above
taking two
x> y^2 and x> y still for fraction it may happen that x^3< y so INSUFF
choose E.
BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course
Redeem
Target Test Prep GMAT OnDemand
Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.
- 715+ score guarantee — highest in the industry (99th percentile)
- 52 chapters · 1,500+ lessons · 4,000+ practice questions
- 400 hours of video · 1,500+ instructor-led HD smartboard lessons
- 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
- 24/7 live support + weekly Zoom office hours with GMAT instructors
- TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
- 1,200+ flashcards + AI-powered study assistant & daily calendar
- OnDemand, LiveTeach & GMAT Bootcamp formats available
- Also: GRE, SAT Math & Executive Assessment courses
- MBA Admissions Consulting now available
- 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
- 200,000+ students served
- 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★
5.0
(559 reviews)
130-pt guarantee
$0 to start
then $127/mo
> or < an interesting one
Source: Beat The GMAT — Data Sufficiency |
I noticed that the GMAT loves to test your knowledge of fractions with exponents and how they get smaller as they are raised to a power (or a square root of a fraction gets bigger, like in this example).
Remember to always check with negative numbers and fractions unless the problem explicitly states otherwise.
Remember to always check with negative numbers and fractions unless the problem explicitly states otherwise.
E for me as well.
take both the statements together
take x=.5 and y = .2 => x^3 < y
take x=4 and y = 1 => x^3 > y
Hence insufficient.
take both the statements together
take x=.5 and y = .2 => x^3 < y
take x=4 and y = 1 => x^3 > y
Hence insufficient.
can I solve this problem by
1.
y<x^3 only when x<x^3
only when x>1
and there is infomation of x
not sufficient
we do the same for 2,
E is correct.
Can I do like this
1.
y<x^3 only when x<x^3
only when x>1
and there is infomation of x
not sufficient
we do the same for 2,
E is correct.
Can I do like this
















