If (10^50) – 74 is written as an integer in base 10 notation, what is the sum of the digits in
that integer?
A. 424
B. 433
C. 440
D. 449
E. 467
that integer?
A. 424
B. 433
C. 440
D. 449
E. 467
10^50 will be 1 and 50 zeroes ... subtracting 74 from it u wuld have 48 9's and 2,6 ... that is the number wuld be 999999 .. 48times .. 26 ... so the sum of the digits will be ... 48*9+2+6= 432+8 = 440 ... ans C ..f2001290 wrote:If (10^50) – 74 is written as an integer in base 10 notation, what is the sum of the digits in
that integer?
A. 424
B. 433
C. 440
D. 449
E. 467
