One fourth of a solution that was 10% sugar by weight was replaced by a second solution resulting in a solution that was 16 percent sugar by weight. The second solution was what percent sugar by weight?
A. 34%
B. 24%
C. 22%
D. 18%
E. 8.5%
The OA is A.
I get the solution as follow,
let 100 be the total volume.
total salt = 10
salt taken out = 10/4 = 2.5
to make solution 16%, total salt = 16
salt added = 16-7.5 = 8.5
solution had = 8.5/25*100 = 34% sugar.
I would like that any expert explains another way to solve this PS question, please! Thanks in advance!
A. 34%
B. 24%
C. 22%
D. 18%
E. 8.5%
The OA is A.
I get the solution as follow,
let 100 be the total volume.
total salt = 10
salt taken out = 10/4 = 2.5
to make solution 16%, total salt = 16
salt added = 16-7.5 = 8.5
solution had = 8.5/25*100 = 34% sugar.
I would like that any expert explains another way to solve this PS question, please! Thanks in advance!
