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On Monday, the regular price of widget was discounted by 25 percent. On Tuesday, the...

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by BTGmoderatorLU » Tue Apr 07, 2020 1:53 am

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Source: Magoosh

On Monday, the regular price of a widget was discounted by 25 percent. On Tuesday, the reduced price was discounted by 50 percent. If the final price was $60, what was the regular price?

A. $135
B. $150
C. $160
D. $175
E. $180

The OA is C
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Re: On Monday, the regular price of widget was discounted by 25 percent. On Tuesday, the...

by Brent@GMATPrepNow » Tue Apr 07, 2020 5:44 am
BTGmoderatorLU wrote: ↑
Tue Apr 07, 2020 1:53 am
 Source: Magoosh

On Monday, the regular price of a widget was discounted by 25 percent. On Tuesday, the reduced price was discounted by 50 percent. If the final price was $60, what was the regular price?

A. $135
B. $150
C. $160
D. $175
E. $180

The OA is C
Let x = the ORIGINAL (regular) price

On Monday, the regular price of a widget was discounted by 25 percent.
If the price is discounted 25%, then we end up paying 75% of the ORIGINAL price
In other words, the discounted price = 75% of x = 0.75x

On Tuesday, the reduced price was discounted by 50 percent.
In other words, we end up paying 50% of the pre-discounted price
So: NEW discounted price = 50% of 0.75x = (0.50)(0.75x) = 0.375x

If the final price was $60, what was the regular price?
We can write: 0.375x = 60
Solve: x = 160

Answer: C

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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Re: On Monday, the regular price of widget was discounted by 25 percent. On Tuesday, the...

by Scott@TargetTestPrep » Fri Apr 10, 2020 2:51 am
BTGmoderatorLU wrote: ↑
Tue Apr 07, 2020 1:53 am
 Source: Magoosh

On Monday, the regular price of a widget was discounted by 25 percent. On Tuesday, the reduced price was discounted by 50 percent. If the final price was $60, what was the regular price?

A. $135
B. $150
C. $160
D. $175
E. $180

The OA is C
We let n = the regular price of the widget. We can create the equation:

n x 3/4 x 1/2 = 60

3n/8 = 60

3n = 480

n = 160

Answer: C

Scott Woodbury-Stewart
Founder and CEO
[email protected]

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