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Which of the following, if solved, would yield the set of all real numbers that are exactly 15 units away from -3?

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by BTGmoderatorDC » Sun Mar 27, 2022 3:24 am

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Which of the following, if solved, would yield the set of all real numbers that are exactly 15 units away from -3?


A. |x + 3| = 15
B. |x - 3| = 15
C. |x - 15| = 3
D. |x + 15| = 3
E. |x + 15| = -3


OA A

Source: Veritas Prep
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Source: — Problem Solving |

BTGmoderatorDC wrote:
Sun Mar 27, 2022 3:24 am
Which of the following, if solved, would yield the set of all real numbers that are exactly 15 units away from -3?


A. |x + 3| = 15
B. |x - 3| = 15
C. |x - 15| = 3
D. |x + 15| = 3
E. |x + 15| = -3


OA A

Source: Veritas Prep
\(15\) units away from \(-3 = -3+15=12\) and \(-3-15=-18\)

In A we have
\(x+3=15\)
\(x=12\)

and

\(-x-3=15\)
\(x=-18\)

Therefore, A
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