ska7945 wrote:On a certain transatlantic crossing, 20 percent of a ship’s passengers held round-trip tickets and also took their cars abroad the ship. If 60 percent of the passengers with round-trip tickets did not take their cars abroad the ship, what percent of the ship’s passengers held round-trip tickets?
A. 33.3%
B. 40%
C. 50%
D. 60%
E. 66.3%
Percent question with an unknown total: let's pick 100 to get the ball rolling.
There are 100 total passengers.
20 of them have round-trip tickets AND cars.
Since 60 percent of the passengers with round-trip tickets did NOT take their cars abroad the ship, we know that 40% of the passengers with round-trip tickets DID take their cars.
Accordingly, if we let R = # of round trip ticket holders:
40%(R) = 20
(2/5)R = 20
R = 20(5/2)
R = 50
choose (C).
