Is x > 10^10 ?
(1) x > 2^34
2^34=(2^10)(2^10)(2^10)(2^4)
=(1024)(1024)(1024)(16)
=(10^3)(10^3)(10^3)(10*1.6)
=1.6*10^10 (approximately) > 10^10
SUFFICIENT
(2) x = 2^35
3.2*10^10 (approximately) > 10^10
SUFFICIENT
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A quick way?
Source: Beat The GMAT — Data Sufficiency |
Thanks....guess i blanked out here.....2^10=10^2 (approx.)sanabk wrote:Is x > 10^10 ?
(1) x > 2^34
2^34=(2^10)(2^10)(2^10)(2^4)
=(1024)(1024)(1024)(16)
=(10^3)(10^3)(10^3)(10*1.6)
=1.6*10^10 (approximately) > 10^10
SUFFICIENT
(2) x = 2^35
3.2*10^10 (approximately) > 10^10
SUFFICIENT
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Since we don't need to determine the exact value of x, we can approximate. Here's a quick way:singhsa wrote:Is x > 10^10 ?
(1) x > 2^34
(2) x = 2^35
Is there a quick way to solve this ?
OA - D
10^10 = (2*5)^10 = (2*2*2*1.2)^10 = (2^3)^10 * (1.2)^10 = (2^30)*6 = approximately.
So the question becomes: Is x > (2^30)*6?
1. 2^34 = (2*30)*(2^4) = (2^30)*16. (2^30)*16 > (2^30)*6. Sufficient.
2. Since we saw in statement 1 that 2^34 > (2^30)*6, we know that 2^35 > (2^30)*6. Sufficient.
The correct answer is D.
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Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
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