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Thanks....guess i blanked out here.....2^10=10^2 (approx.)sanabk wrote:Is x > 10^10 ?
(1) x > 2^34
2^34=(2^10)(2^10)(2^10)(2^4)
=(1024)(1024)(1024)(16)
=(10^3)(10^3)(10^3)(10*1.6)
=1.6*10^10 (approximately) > 10^10
SUFFICIENT
(2) x = 2^35
3.2*10^10 (approximately) > 10^10
SUFFICIENT
Since we don't need to determine the exact value of x, we can approximate. Here's a quick way:singhsa wrote:Is x > 10^10 ?
(1) x > 2^34
(2) x = 2^35
Is there a quick way to solve this ?
OA - D
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