vinni.k wrote:Is y - x > 1/(x - y) ?
(1). |x - y| > 1
(2). y > x
Answer is B
Thanks & Regards
Vinni
Another approach to this problem is to invent our own little third unknown called "z." If we say that z = y - x, then -z = x - y. So then the question becomes, "Is z > 1/-z?"
*THAT* question is much, much easier to answer. The answer will be YES if z is positive and NO if z is negative.
So the question becomes, "Is z positive?" and therefore, "Is y - x positive?" or, in other words, "Is y - x > 0?"
Or, more ominously, "Is y > x?"
STATEMENT 1 needs to be reduced. How to reduce it depends on whether x is greater than y.
If x is greater than or equal to y, the statement becomes x - y > 1 or x > y + 1. This would clearly make the answer to our question NO.
If y is greater than x, the statement becomes y - x > 1 or y > x + 1. This would clearly make the answer to our question YES.
So statement 1 is not sufficient to give a definitive yes or a definitive no.
STATEMENT 2, on the other hand, gives us nothing less than the reductive condition of the goal statement we wanted to verify. So, it is sufficient to say definitely YES.
