Randy can rebuild an automobile engine in a hours. Alvin can rebuild the same engine in b hours. If Randy and Alvin work together at their respective rates to rebuild the engine, which of the following represents the portion of the job that Randy will not have to complete?
A. ab/(a+b)
B. (a-b)/(a+b)
C. b/(b-a)
D. a/(a+b)
E. b/(a+b)
Help..!
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- cypherskull
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- neelgandham
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If Randy can rebuild an automobile engine in a hours. What part of the automobile can he rebuild in 1 hour ? It is 1/a
Similarly, If Alvin can rebuild the same engine in b hours. What part of the automobile can he rebuild in 1 hour ? It is 1/b.
In one hour Randy and Alvin working together can rebuild (1/a + 1/b)th part of an automobile.
Total time taken by Randy and Alvin to rebuild the automobile = 1/(1/a + 1/b) = ab/(a+b) hours
Portion of work Randy completed in ab/(a+b) hours = [ab/(a+b)]*1/a = b/(a+b)
Portion of work Randy will not have to complete = 1 - [b/(a+b)] = a/(a+b)
IMO D
A. ab/(a+b)
B. (a-b)/(a+b)
C. b/(b-a)
D. a/(a+b)
E. b/(a+b)
Similarly, If Alvin can rebuild the same engine in b hours. What part of the automobile can he rebuild in 1 hour ? It is 1/b.
In one hour Randy and Alvin working together can rebuild (1/a + 1/b)th part of an automobile.
Total time taken by Randy and Alvin to rebuild the automobile = 1/(1/a + 1/b) = ab/(a+b) hours
Portion of work Randy completed in ab/(a+b) hours = [ab/(a+b)]*1/a = b/(a+b)
Portion of work Randy will not have to complete = 1 - [b/(a+b)] = a/(a+b)
IMO D
A. ab/(a+b)
B. (a-b)/(a+b)
C. b/(b-a)
D. a/(a+b)
E. b/(a+b)
Anil Gandham
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- cypherskull
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Thanks Anil! That helped.
Regards,
Sunit
________________________________
Kill all my demons..And my angels might die too!
Sunit
________________________________
Kill all my demons..And my angels might die too!